Both should be yes..there is exactly one x input for every y input
Answer:

Step-by-step explanation:
- IMPORTANT FORMULA: the standard equation of a hyperbola whose transverse axis is parallel to the y axis is:

where, (h,k) : center of the hyperbola
a : semi conjugate axis [ length of conjugate axis/2]
b: semi transverse axis [ length of transverse axis/2]
- so, here a=3, b=7, [h,k]=[-5,8]
- by substituting these values in the above given formula,
- the equation of the hyperbola in standard form is :


Answer:
0.2036
Step-by-step explanation:
u = arcsin(0.391) ≈ 23.016737°
tan(u/2) = tan(11.508368°)
tan(u/2) ≈ 0.2036
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You can also use the trig identity ...
tan(α/2) = sin(α)/(1+cos(α))
and you can find cos(u) as cos(arcsin(0.391)) ≈ 0.920391
or using the trig identity ...
cos(α) = √(1 -sin²(α)) = √(1 -.152881) = √.847119
Then ...
tan(u/2) = 0.391/(1 +√0.847119)
tan(u/2) ≈ 0.2036
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<em>Comment on the solution</em>
These problems are probably intended to have you think about and use the trig half-angle and double-angle formulas. Since you need a calculator anyway for the roots and the division, it makes a certain amount of sense to use it for inverse trig functions. Finding the angle and the appropriate function of it is a lot easier than messing with trig identities, IMO.
17500/5 = 3500 ( down payment )
17500 - 3500 = 14000
14000/100 = 140
140 x 4 = 560 ( CD account )
14000 - 560 = 13440
13400/100 = 134.4
let's firstly convert the mixed fractions to improper fractions and then add, bearing in mind that the LCD from 8 and 4 is simply 8.
![\bf \stackrel{mixed}{5\frac{7}{8}}\implies \cfrac{5\cdot 8+7}{8}\implies \stackrel{improper}{\cfrac{47}{8}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{47}{8}+\cfrac{11}{4}\implies \stackrel{\textit{using the LCD of 8}}{\cfrac{(1)47~~-~~(2)11}{8}}\implies \cfrac{47-22}{8}\implies \cfrac{25}{8}\implies 3\frac{1}{8}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B5%5Cfrac%7B7%7D%7B8%7D%7D%5Cimplies%20%5Ccfrac%7B5%5Ccdot%208%2B7%7D%7B8%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B47%7D%7B8%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B47%7D%7B8%7D%2B%5Ccfrac%7B11%7D%7B4%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Busing%20the%20LCD%20of%208%7D%7D%7B%5Ccfrac%7B%281%2947~~-~~%282%2911%7D%7B8%7D%7D%5Cimplies%20%5Ccfrac%7B47-22%7D%7B8%7D%5Cimplies%20%5Ccfrac%7B25%7D%7B8%7D%5Cimplies%203%5Cfrac%7B1%7D%7B8%7D)