Answer:
1 stack of 36
Step-by-step explanation:
First find how much one carton can hold
length is 45
width is 20
height is 40
40 * 20 * 45 = 36,000
Then find how much volume each box has
length is 20
width is 10
height is 5
5 * 10 * 20 = 1000
so each box is 1000 volume
1 stack of 36 is good
Answer:
DE = 13.4 cm (to 1 decimal place)
Step-by-step explanation:
Given: ABCD is a square
BC = AC = 12 cm (opposite sides of a square are congruent)
E is midpoint of BC (given)
BE = EC = 12/2 = 6 cm
CD = AB = 12 cm (opposite sides of a square are congruent)
angle ECD is a right angle (interior angles of a square are 90 deg.)
Consider right triangle ECD
DE = sqrt(EC^2+CD^2) ............. pythagorean theorem
= sqrt(6^2+12^2)
= sqrt ( 36+144 )
= sqrt (180)
= 2 sqrt(45)
= 13.416 (to three dec. places)
To solve this problem, we first have to convert 5 1/2 into an improper fraction. To do this, we multiply the unit (5) times the denominator (2) and then add the numerator (1) to the product, while still keeping the same denominator.
(5 * 2) + 1 = 10 + 1 = 11/2
Now, this makes our expression: 11/2 - 2/3
Next, we have to find a common denominator for 2 and 3 by finding their shared LCM, or least common multiple. In this case, the LCM is 6. This means that we are going to convert both of the fractions in the expression into fractions with the denominator 6, so that we can easily compute the subtraction.
11 * 3 / 2 * 3 - 2 * 2 / 3 * 2
33/6 - 4/6
Now, we can simply subtract the numerators to find our final answer.
29/6
Your final answer is 29/6.
Hope this helps!
Given:
The bases of a trapezoid lie on the lines
To find:
The equation that contains the midsegment of the trapezoid.
Solution:
The slope intercept form of a line is
Where, m is slope and b is y-intercept.
On comparing with slope intercept form, we get
On comparing with slope intercept form, we get
The slope of parallel lines are equal and midsegment of a trapezoid is parallel to the bases. So, the slope of the bases line and the midsegment line are equal.
The y-intercept of one base is 7 and y-intercept of second base is -5. The y-intercept of the midsegment is equal to the average of y-intersects of the bases.
So, the y-intercept of the required line is 1.
Putting m=2 and b=1 in slope intercept form, we get
Therefore, the equation of line that contains the midsegment of the trapezoid is .
