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2 years ago

Subtract. Write your answer as a fraction in simplest form. -83/8-101/6

Mathematics

1 answer:

ludmilkaskok [199]2 years ago

5 0

Answer:

Step-by-step explanation:

-653/24

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The triangles below are congruent, with △ABC ≅ △DEF. The following lengths are given in centimeters: AB⎯⎯⎯⎯⎯ = x + 1, AC⎯⎯⎯⎯⎯ =

stiks02 [169]

Answer:

It is Def because in a game Def means defend

Step-by-step explanation:

5 0

2 years ago

Peter has 6 sweaters, 4 pairs of jeans, and 3 pairs of shoes. how many different outfits can peter make using one sweater, one p

sdas [7]

The answer is 72 because 6x4x3=72

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2 years ago

in exercises 15-20 find the vector component of u along a and the vecomponent of u orthogonal to a u=(2,1,1,2) a=(4,-4,2,-2)

Nimfa-mama [501]

Answer:

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

Step-by-step explanation:

Let $\vec u$ and $\vec a$ , from Linear Algebra we get that component of $\vec u$ parallel to $\vec a$ by using this formula:

$\vec u_{\parallel \,\vec a} = \frac{\vec u \bullet\vec a}{\|\vec a\|^{2}} \cdot \vec a$ (Eq. 1)

Where $\|\vec a\|$ is the norm of $\vec a$ , which is equal to $\|\vec a\| = \sqrt{\vec a\bullet \vec a}$ . (Eq. 2)

If we know that $\vec u =(2,1,1,2)$ and $\vec a=(4,-4,2,-2)$ , then we get that vector component of $\vec u$ parallel to $\vec a$ is:

$\vec u_{\parallel\,\vec a} = \left[\frac{(2)\cdot (4)+(1)\cdot (-4)+(1)\cdot (2)+(2)\cdot (-2)}{4^{2}+(-4)^{2}+2^{2}+(-2)^{2}} \right]\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\frac{1}{20}\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

Lastly, we find the vector component of $\vec u$ orthogonal to $\vec a$ by applying this vector sum identity:

$\vec u_{\perp\,\vec a} = \vec u - \vec u_{\parallel\,\vec a}$ (Eq. 3)

If we get that $\vec u =(2,1,1,2)$ and $\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$ , the vector component of $\vec u$ is:

$\vec u_{\perp\,\vec a} = (2,1,1,2)-\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

$\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

4 0

2 years ago

Diego chose a number to represent the input of the machine shown and `40` was the result. What is the input? I think it is 14, b

Simora [160]

Answer:

Step-by-step explanation:

it is 14 because when you divide 40 to 14 it is ...

5 0

2 years ago

PLEASE HELP which statement is true about the system x-3y=5 and y=x-7

LuckyWell [14K]

Answer: C

Step-by-step explanation:

x-3y=5, y=x-7 *solve it

the answer is (8,1)

so..

C. (8,1) is a solution to both equations so it is a solution to the system

4 0

2 years ago