3 years ago

Solve for y. -y/3 = -23 simplify your answer as much as possible

Mathematics

2 answers:

ella [17]3 years ago

8 0

Answer:

Step-by-step explanation:

We multiply both sides of the equation by 3 to cancel out the denominator. That gives us -y=-69. Since we cannot have a negative variable, we change the values on both sides, giving us y=69

qwelly [4]3 years ago

7 0

Answer:

Step-by-step explanation:

-y/3 = -23

=> -y = -23 x 3

=> -y = -69

=> y = 69

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Zina [86]

9514 1404 393

Answer:

y = -2/3x +5/3
y = 2.4x -8

Step-by-step explanation:

Solve for y. The slope (m) is the coefficient of x. The y-intercept (b) is the constant.

1. 3y = -2x +5

y = -2/3x +5/3 . . . . . m = -2/3, b = 5/3

2. y = 2.4x -8 . . . . . . . m = 2.4, b = -8

8 0

2 years ago

Can someone help me with this problem? It has to be in PEMDAS order. 16+(4*2/2)-4

ryzh [129]

Answer:16

Step-by-step explanation:

4*2 is 8/2 is 4 + 16 is 20 - 4 is 16

6 0

3 years ago

Read 2 more answers

Evaluate 5(a•4)+ b, 1 when a=-andb=12. 3 O A) 14 3 OB) 17 2 O C) 18 3 OD) 27<br><br><br>HELP ASAP

svetlana [45]

Evaluate 5(a•4)+ b, when a = 1/3 and b=12

The Answer is

C. 18 2/3

hope it's help hshshs

3 0

3 years ago

Please help i’m doing trying to do my gf work please i’ll give you brainliest

otez555 [7]

Answer:

t = 5 seconds h = 128 feet

Step-by-step explanation:

The given equation of the object is :

$h(t)=-16t^2+64t+80$ .....1

When it hits the ground,

h(t) = 0

So,

$-16t^2+64t+80=0\\\\t=-1\ s\ and\ t=5\ s$

The object will hit the ground in 5 seconds.

Now, put t = 1 s in equation (1).

$h(1)=-16(1)^2+64(1)+80\\\\h(t)=128\ ft$

The object is at a height of 128 ft at 1 second.

7 0

3 years ago

Please show the steps I need this right now I’m taking a test8(x−4)<7x−3

Olegator [25]

Answer:

x < 29

Step-by-step explanation:

8(x−4)<7x−3; distribute 8 in the parenthesis

8x - 32 < 7x - 3; subtract 7x from both sides

x - 32 < -3; add 32 to both sides

x < 29

5 0

3 years ago