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3 years ago

Solve for y. -y/3 = -23 simplify your answer as much as possible

Mathematics

2 answers:

ella [17]3 years ago

8 0

Answer:

Step-by-step explanation:

We multiply both sides of the equation by 3 to cancel out the denominator. That gives us -y=-69. Since we cannot have a negative variable, we change the values on both sides, giving us y=69

qwelly [4]3 years ago

7 0

Answer:

Step-by-step explanation:

-y/3 = -23

=> -y = -23 x 3

=> -y = -69

=> y = 69

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Find the missing length

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the answer is 46

Step-by-step explanation:

8 + 20 + 18 = 46

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In 3.75 years, you will have $865.30

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Write a function to model set of data

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Solve the system of equation by guess sidle method

lilavasa [31]

Answer: The solution is,

$x_1\approx 0.876$

$x_2\approx 0.419$

$x_3\approx 0.574$

Step-by-step explanation:

Given equations are,

$8x_1 + x_2 + x_3 = 8$

$2x_1 + 4x_2 + x_3 = 4$

$x_1 + 3x_2 + 5x_3 = 5$ ,

From the above equations,

$x_1=\frac{1}{8}(8-x_2-x_3)$

$x_2=\frac{1}{4}(4-2x_1-x_3)$

$x_3=\frac{1}{5}(5-x_1-3x_2)$

First approximation,

$x_1(1)=\frac{1}{8}(8-(0)-(0))=1$

$x_2(1)=\frac{1}{4}(4-2(1)-(0))=0.5$

$x_3(1)=\frac{1}{5}(5-1-3(0.5))=0.5$

Second approximation,

$x_1(2)=\frac{1}{8}(8-(0.5)-(0.5))=0.875$

$x_2(2)=\frac{1}{4}(4-2(0.875)-(0.5))=0.4375$

$x_3(2)=\frac{1}{5}((0.875)-3(0.4375))=0.5625$

Third approximation,

$x_1(3)=\frac{1}{8}(8-(0.4375)-(0.5625))=0.875$

$x_2(3)=\frac{1}{4}(4-2(0.875)-(0.5625))=0.421875$

$x_3(3)=\frac{1}{5}(5-(0.875)-3(0.421875))=0.571875$

Fourth approximation,

$x_1(4)=\frac{1}{8}(8-(0.421875)-(0.571875))=0.875781$

$x_2(4)=\frac{1}{4}(4-2(0.875781)-(0.571875))=0.419141$

$x_3(4)=\frac{1}{5}(5-(0.875781)-3(0.419141))=0.573359$

Fifth approximation,

$x_1(5)=\frac{1}{8}(8-(0.419141)-(0.573359))=0.875938$

$x_2(5)=\frac{1}{4}(4-2(0.875938)-(0.573359))=0.418691$

$x_3(5)=\frac{1}{5}(5-(0.875938)-3(0.418691))=0.573598$

Hence, by the Gauss Seidel method the solution of the given system is,

$x_1\approx 0.876$

$x_2\approx 0.419$

$x_3\approx 0.574$

4 0

3 years ago

a+solution+of+salt+and+water+contains+75+grams+of+water+per+150+mililiters+of+the+solution.+if+1+mole+of+water+weighs+16+grams,+

bazaltina [42]

A solution of salt and water contain 75 grams of water per 150 millimeters of the solution. If 1 mole of water weight 16 grams, how many moles of water would be present in 30 mil liter of the solution.
Kindly mark as brainliest

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3 years ago