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ANEK [815]
3 years ago
8

Find the value of 4(5)+12÷3 (8)+2 (-4)

Mathematics
2 answers:
Firlakuza [10]3 years ago
6 0
The answer is 44 because all you have to do is use PEMDAS to solve the equation
Greeley [361]3 years ago
5 0
The answer for that question is 44
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Evaluate:<br><br> -7 - (-8) + (-3) + 6 - 2<br><br> A) -2 <br> B) 0 <br> C) 1 <br> D) 2
Gala2k [10]

Answer:

D) 2

Step-by-step explanation:

4 0
3 years ago
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PLEASE HELP!!!! URGENT. 20 POINTS AND ILL GIVE YOU BRAINLIEST!!
Leokris [45]

Answer:

magma blocks

Step-by-step explanation:

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3 0
2 years ago
Find the value of each variable
kondaur [170]

Answer:

The correct answer is option C

a = 10√3, b = 5√3, c = 15 and d = 5

Step-by-step explanation:

Points to remember

The angles of a right angled triangle, 30°, 60° and 90° then sides are in the ratio, 1: √3 : 2

<u>To find the value of variables</u>

From the figure we can see 2 right angled triangle with angle 30, 60 and 90

we get, d= 5 then b = 5√3

b = 5√3  the c = 5√3 * √3 = 15

and a = 2 * 5√3 = 10√3

Therefore the correct answer is option C

a = 10√3, b = 5√3, c = 15 and d = 5

4 0
3 years ago
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The volume of a cone varies jointly with the area of the base and the height. when the area of the base is
strojnjashka [21]
The volume of a cone varies jointly with the area of the base and the height of the cone.

V = kAh

where
V = volume
k = constant of proportionality
A = area of the base
h = height of the cone

The given info is for A = 27, and h = 6, then V = 54 (all using appropriate units for area, length, and volume, respectively.)

Now we can find k, the constant of proportionality.

V = kAh

54 = k * 27 * 6

k = 54/(27 * 6)

k = 1/3

The formula is

V = \dfrac{1}{3}Ah

Now we use the second set of info, the height and the volume, and we find the area of the base.

V = \dfrac{1}{3}Ah

124 = \dfrac{1}{3} \times A \times 12

124 = 4A

A = 31

Answer: the area of the base is 31 cm^2
3 0
3 years ago
Need help please I don’t get it
shutvik [7]

Answer:

question is not clear and I think you are doing cheating in this test

7 0
2 years ago
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