What is an equation of the line that passes through the points (1, 2) and (2, -1)?
1 answer:
Answer:
slope(m) = y2 -y1/ x2 - x1
m = -1 - 2/ 2 - 1
m = -3/1 ; m = -3
using the formula y -y1 = m(x - x1)
y - 2 = -3( x -1)
y -2 = -3x +3
collect like terms
3 +2 = y + 3x
y + 3x = 5
y = -3x + 5( y = mx + c)
equation of the line= y = -3x + 5
You might be interested in
Answer:
using Pythagoras theorem
breadth = √25^2 -24^2
=√47
= 7cm
P = 24+7+24+7 = 62
Answer:
this is the graph to the equation :) hope this helps in all ways possible:)
Step-by-step explanation:
Answer:
x=5
Step-by-step explanation:
First we distribute
2x-4=6
isolate x
2x=10
divide both sides by 2
x=5
(plz give brianliest ty)
Answer:
area = 12 m²
Step-by-step explanation:
area = L x W
area = 4 x 3 = 12 m²
Step-by-step explanation:
let m2 be x
then m1 = 4x
Since, m1+m2 = 115
therefore x + 4x = 115
5x = 115
x = 23
so , m2 = 23°
