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mihalych1998 [28]
2 years ago
6

What is an equation of the line that passes through the points (1, 2) and (2, -1)?

Mathematics
1 answer:
Alex Ar [27]2 years ago
8 0

Answer:

slope(m) = y2 -y1/ x2 - x1

m = -1 - 2/ 2 - 1

m = -3/1 ; m = -3

using the formula y -y1 = m(x - x1)

y - 2 = -3( x -1)

y -2 = -3x +3

collect like terms

3 +2 = y + 3x

y + 3x = 5

y = -3x + 5( y = mx + c)

equation of the line= y = -3x + 5

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Answer:

Step-by-step explanation:

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Answer:

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The Fundamental Theorem tells us this 3rd-degree polynomial will have 3 roots.

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__

The graph in the third attachment (red) shows there are no turning points, hence no relative extrema. The end behavior, as for any odd-degree polynomial with a positive leading coefficient, is down to the left and up to the right.

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