Answer:
8x + 23
Step-by-step explanation:
-7(x-5) - 3(4-5x)
= -7x + 35 - 12 + 15x
= 8x + 23
Greetings!
Here is how we simplify the following expression:
![=\frac{500}{4\frac{13}{14}}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B500%7D%7B4%5Cfrac%7B13%7D%7B14%7D%7D)
First, convert the mixed number into a improper fraction. Not sure how to do that? Here is a guide:
→ Multiply the whole number by the denominator of the fraction:
⇒ ![(4)(14)=56](https://tex.z-dn.net/?f=%20%284%29%2814%29%3D56%20)
→ Add the product to the numerator of the fraction:
⇒ ![56+13=69](https://tex.z-dn.net/?f=%2056%2B13%3D69%20)
The improper fraction would be: ![\boxed{\frac{69}{14}}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Cfrac%7B69%7D%7B14%7D%7D)
![= \frac{500}{\frac{69}{14}}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B500%7D%7B%5Cfrac%7B69%7D%7B14%7D%7D)
Flip the numerator and denominator to turn the division into multiplication:
![=(500)(\frac{14}{69})](https://tex.z-dn.net/?f=%20%3D%28500%29%28%5Cfrac%7B14%7D%7B69%7D%29%20%20)
![=(\frac{500}{1})(\frac{14}{69})](https://tex.z-dn.net/?f=%20%3D%28%5Cfrac%7B500%7D%7B1%7D%29%28%5Cfrac%7B14%7D%7B69%7D%29%20%20)
Multiply the numerators of the fractions by each other. Complete the same thing with the denominators. <em>Example:
</em>
![=\frac{(500)(14)}{(1)(69)}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%28500%29%2814%29%7D%7B%281%29%2869%29%7D)
![=\frac{7000}{69}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B7000%7D%7B69%7D)
The Answer is:
![\boxed{=\frac{7000}{69}}](https://tex.z-dn.net/?f=%5Cboxed%7B%3D%5Cfrac%7B7000%7D%7B69%7D%7D)
I hope this helped!
-Benjamin
Answer:
837150
/7
Step-by-step explanation:
459(
569
/7
)+997
=
830171
/7
+997
=
837150
/7
So here is the answer.
We represent h = hardwood and p = pine bark
Here is the equation: h + p = 176
2.75p + 3.50h = 520
Next, p = 176 -h (substitute)
2.75 (176-h) + 3.5h = 520
484 -2.75h + 3.5h = 520
3.5h-2.75h = 520 -484
0.75h = 36 (divide both by 0.75)
h = 48
Therefore, the number of hardwood sold is 48.
h + p = 176
p = 176-48
p= 128
The number of pine bark sold is 128.
Hope this helps.