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PSYCHO15rus [73]
3 years ago
10

Michael bought six books that cost d dollars each.Write an equation that can be used to show the total cost (c)of the books?How

much would Michael spend if each book cost $7.89?​
Mathematics
2 answers:
yulyashka [42]3 years ago
8 0

Step-by-step explanation:

Equation is 6d (6 • d)

Actual Question:

c = 6d

Let d = 7.89

c= 6 (7.89)

c = 47.34

Michael would have spent a total of $47.34.

zysi [14]3 years ago
8 0

Answer:

Equation: c = 6d

Total cost: $47.34

Step-by-step explanation:

Equation:

c = 6d

Where c is the total cost and d is the price a book

In order to find the total cost, you must multiply the price of something by the number of items you bought; therefore the equation above accurately represents the problem.

Substitute:

c = 6d

c = 6(7.89)

Multiply:

c = 6(7.89)

c = 47.34

In conclusion, Michael would spend $47.34 on 6 books.

Hope this helps :)

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answer

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Step-by-step explanation:

35.42 + 18 -1.89 +35

he has 87.53 this is enough for the skateboard

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Answer:

8 3/4 inches

Step-by-step explanation:

Total length of the rod = 24 1/2 inches

Carlos = 8 3/4 inches

Amanda = 6 3/8 inches

length of the rod remaining = Total length - ( Carlos + Amanda)

= 24 1/2 - (8 3/4 + 6 3/8)

= 49/2 - (35/4 + 51/8)

= 49/2 - ( 75+51/8)

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6 0
4 years ago
Please help need assistance
SOVA2 [1]

Answer:

18

Step-by-step explanation:

Keep in mind that anything with a subscript of 0 always comes out as a 1

16(1)+2(2)²(4⁻¹)

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Hope this helps! :)

7 0
3 years ago
Need help #1. The answer is shown, but I don’t know how to get to the answer. Please teach and show steps.
Rufina [12.5K]

Answer:

B

Step-by-step explanation:

We are given that <em>x</em> and <em>y</em> are functions of time <em>t</em> such that <em>x</em> and <em>y</em> is a constant. So, we can write the following equation:

x(t)+y(t)=k,\text{ where $k$ is some constant}

The rate of change of <em>x</em> and the rate of change of <em>y</em> with respect to time <em>t</em> is simply dx/dt and dy/dt, respectively. So, we will differentiate both sides with respect to <em>t: </em>

<em />\displaystyle \frac{d}{dt}\Big[x(t)+y(t)\Big]=\frac{d}{dt}[k]<em />

Remember that the derivative of a constant is always 0. Therefore:

\displaystyle \frac{dx}{dt}+\frac{dy}{dt}=0

And by subtracting dy/dt from both sides, we acquire:

\displaystyle \frac{dx}{dt}=-\frac{dy}{dt}

Hence, our answer is B.

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