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3 years ago

What process do you use to find the percent change of a quantity?

Mathematics

2 answers:

Airida [17]3 years ago

8 0

Answer:

Step-by-step explanation:

First, we need to get the amount of change:

The amount of change can either be an increase or a decrease.

It can be calculated as follows:

amount of change =

If the amount of change is positive, then it is an increase

If the amount of change is negative, then it is a decrease

Then, we need to convert this amount into a percentage:

Changing the amount into a percentage can simply be done by multiplying this amount by 100

This means that:

% of change = amount of change * 100

Combining the two steps:

% of change = * 100

Examples:

The original price of a certain product was $10. It then became $12. Find the % of increase.

% of change = = 20%

This means that the price increased by 20%

The temperature decreased from 25 degrees to 20 degrees. Find the percentage of decrease.

% of decrease = = -20%

This means that the temperature decreased by 20%

Hope this helps :)

Sever21 [200]3 years ago

7 0

First, we need to get the amount of change:
The amount of change can either be an increase or a decrease.
It can be calculated as follows:
amount of change = $\frac{"new"value - "old"value}{"old" value}$

If the amount of change is positive, then it is an increase
If the amount of change is negative, then it is a decrease

Then, we need to convert this amount into a percentage:
Changing the amount into a percentage can simply be done by multiplying this amount by 100
This means that:
% of change = amount of change * 100

Combining the two steps:
% of change = $\frac{"new"value - "old"value}{"old" value}$ * 100

Examples:
The original price of a certain product was $10. It then became $12. Find the % of increase.
% of change = $\frac{12-10}{10} * 100$ = 20%
This means that the price increased by 20%

The temperature decreased from 25 degrees to 20 degrees. Find the percentage of decrease.
% of decrease = $\frac{20-25}{25} * 100$ = -20%
This means that the temperature decreased by 20%

Hope this helps :)

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Write the equation of a vertical ellipse with a major axis of 20, a minor axis of 12, and a center of (6, 3)

maksim [4K]

Answer:

The equation of a vertical ellipse is $\frac{(x-6)^2}{100} + \frac{(y-3)^2}{36} = 1\\$

Step-by-step explanation:

Here, given:

Length of major axis: 20

⇒ 2 a = 20 , or , a = 10

Length of minor axis: 12

⇒ 2 b = 12 , or , b = 6

Also, center (h,k) = (6,3)

Now, STANDARD EQUATION OF ELLIPSE :

$\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1\\$

Now, substituting the values, a, b , h and k in above expression, we get:

$\frac{(x-6)^2}{10^2} + \frac{(y-3)^2}{6^2} = 1\\$

or, $\frac{(x-6)^2}{100} + \frac{(y-3)^2}{36} = 1\\$

Hence, the equation of a vertical ellipse is $\frac{(x-6)^2}{100} + \frac{(y-3)^2}{36} = 1\\$

3 0

3 years ago

ASAP!!! ILL GIVE BRAINLIEST

Ostrovityanka [42]

Answer:

The correct options are 2 and 4.

Step-by-step explanation:

From the given box plot it is clear that

$\text{Minimum value}=20$

$Q_1=25$

$Median=40$

$Q_3=50$

$\text{Maximum value}=110$

We know that these number divides the data in four equal parts.

$Q_1=25\%$

$Median=50%$

$Q_3=75\%$

25% of the data values lies between 50 and 110. Therefore option 1 is incorrect.

Seventy-five percent of the data values lies between 20 and 50. Therefore option 2 is correct.

It is unlikely that there are any outliers. This statement is not true because the is a huge difference between third quartile and maximum value.

Therefore option 3 is incorrect.

The interquartile range is

$IQR=Q_3-Q_1=50-25=25$

Therefore option 4 is correct.

The range is

Range = Maximum-Minimum

$Range=110-20=90$

Therefore option 5 is incorrect.

4 0

3 years ago

A random sample of 300 circuits generated 13 defectives. Use the data to test the hypothesis Upper H Subscript 0 Baseline colon

____ [38]

Complete Question

A random sample of 300 circuits generated 13 defectives. a. Use the data to test

$H_o : p = 0.05$

Versus

$H_1 : p \ne 0.05$

Use α = 0.05. Find the P-value for the test

Answer:

The p-value is $p-value = 0.5949$

Step-by-step explanation:

From the question we are told that

The sample size is n = 300

The number of defective circuits is k = 13

Generally the sample proportion of defective circuits is mathematically represented as

$\^ p = \frac{k}{n}$

=> $\^ p = \frac{13}{300}$

=> $\^ p = 0.0433$

Generally the standard Error is mathematically represented as

$SE = \sqrt{\frac{p(1- p)}{n} }$

=> $SE = \sqrt{\frac{0.05(1- 0.05)}{300} }$

=> $SE = 0.0126$

Generally the test statistics is mathematically represented as

$z = \frac{\^ p - p }{SE}$

=> $z = \frac{0.0433 - 0.05 }{0.0126}$

=> $z = -0.5317$

From the z table the area under the normal curve to the left corresponding to -0.5317 is

$(P < -0.5317 ) = 0.29747$

Generally the p-value is mathematically represented as

$p-value = 2 * P(Z < -0.5317 )$

=> $p-value = 2 * 0.29747$

=> $p-value = 0.5949$

3 0

3 years ago

HELP ME PLS & FAST

Ierofanga [76]

The heads probability is ½ and the two’s probability is 1/6. So ½ x 1/6 gives you 1/12. The answer is A. 1/12. Hope this helps.

8 0

3 years ago

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A recipe calls for 8 ounces of fruit juice for every 32 ounces of soda. How much soda should you use if you use 16 ounces of fru

makkiz [27]

Answer:

64 ounces of soda

Step-by-step explanation:

for every 8 ounces you need 32 ounces of soda and 16 would be two servings of fruit juice so I multiplied 32 by 2 and got 64

8 0

2 years ago