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3 years ago

PLEASE HELP!! WILL MARK BRAINLIEST IF RIGHT!!!

Mathematics

1 answer:

denpristay [2]3 years ago

4 0

Answer:

images are:

W'(-5,0)

X'(0,-9)

Y'(-9,-6)

Z'(-6,-2)

Step-by-step explanation:

use formula p(x,y)=p'(y,-x)

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The revenue equation (in hundreds of millions of dollars) for barley production in a certain country is approximated by R(x) = 0

STatiana [176]

Answer:

The marginal-revenue equation is $R'(x)=0.1226x+1.1584$ .

The marginal revenue for the production of 200,000,000 bushels is $R'(x)=1.4036$ .

The marginal revenue for the production of 650,000,000 bushels is $R'(x)=9.1274$ .

Step-by-step explanation:

The derivative $R'(x)$ of the revenue function is called the marginal revenue function and is the rate of change of revenue with respect to the number of units sold.

We know the revenue function, $R(x) = 0.0613x^{2} +1.1584x+2.4813$ . Therefore, the marginal revenue function is

$R'(x)=\frac{d}{dx}R(x) = \frac{d}{dx}(0.0613x^{2} +1.1584x+2.4813)\\\\=\frac{d}{dx}\left(0.0613x^2\right)+\frac{d}{dx}\left(1.1584x\right)+\frac{d}{dx}\left(2.4813\right)\\\\R'(x)=0.1226x+1.1584$

To find the marginal revenue for the production of:

200,000,000 bushels we use x = 2, since x is in units of hundreds of million of dollars.

$R'(x)=0.1226\cdot \:2+1.1584\\\\R'(x)=0.2452+1.1584\\\\R'(x)=1.4036$

650,000,000 bushels we use x = 65, since x is in units of hundreds of million of dollars.

$R'(x)=0.1226\cdot \:65+1.1584\\\\R'(x)=7.969+1.1584\\\\R'(x)=9.1274$

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3 years ago

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ivolga24 [154]

Answer:

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Step-by-step explanation:

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