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erastovalidia [21]
3 years ago
8

Homework: 6.2_HW

Mathematics
1 answer:
ra1l [238]3 years ago
3 0
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What is the anwer to (1/8)^1/3
mojhsa [17]

Answer:

1/8 ^ 1/3 =

1/2 or 0.5

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3 years ago
Dominic spent 2 3/4 hours on his art project. Rachel worked 1 1/3 times as long on her rt project as Dominic worked. For how man
Travka [436]
Dominic = 2 3/4

Rachel = 1 1/3 x 2 3/4 = 11/3 = 3 2/3 hour

Answer: 3 2/3 hour

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4 years ago
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14. Jerry charges a fee of $45 plus $15 per hour to rent a motorbike. Write an equation to
satela [25.4K]

Answer:

5 hours, y= how much money it will cost, and x represents how many hours

Step-by-step explanation:

y= 15x+45

120= 15x+45

-45 -45

75= 15x

75/15×= 5 hours

8 0
3 years ago
SOLVE THE PROPORTION BELOW <br>8/x = 2/3<br>x=<br>A. 10<br>B. 9<br>C. 11<br>D. 12
Fynjy0 [20]
The correct answer is D.12
7 0
3 years ago
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A rectangular vegetable patch has a perimeter of 28 meters and an area of 48 square
aliina [53]

Answer:

Length = 8 meters

Width = 6 meters

Step-by-step explanation:

Given the following information:

Perimeter of a rectangular vegetable patch: 2(L + W) = 28 meters

Area = L × W = 48 m²

We can solve for the dimensions by using both equations.

First, let's use the formula for the perimeter of the rectangular vegetable patch, and isolate one of the given variables:

2(L + W) = 28

Divide both sides by 2:

\frac{2(L + W)}{2} = \frac{28}{2}

L + W = 14

Subtract W from both sides to isolate L:

L + W - W = 14 - W

L = 14 - W

Next, we'll take the formula for the area, and substitute the value for the L from our previous step:

A = 48  =  L × W

48  = W × (14 - W)

Distribute W into the parenthesis:

48 = 14W - W²

Add W² and subtract 14W to both sides:

W² - 14W + 48 = 14W - 14W - W² + W²

W² - 14W + 48 = 0   ⇒ This represents a quadratic equation in standard form. We can use the coefficient and constant values to solve for its roots.

a = 1, b = -14, and c = 48

Substitute these values into the quadratic equation:

x = \frac{-b +/- \sqrt{b^{2}-4ac}}{2a}

x = \frac{14 +/- \sqrt{(-14)^{2}-4(1)(48)}}{2(1)}

x = \frac{14 +/- \sqrt{196-192}}{2}

x = \frac{14 +/- \sqrt{4}}{2}

x = \frac{14 + 2}{2}, x = \frac{14 - 2}{2}

x = 8, x = 6

Now, we can substitute these values into the formulas for the perimeter and area to find the true dimensions of the rectangular vegetable patch.

Perimeter: 2(L + W) = 2(8 + 6) = 28 meters

Area = L × W = 8 × 6  = 48 m²

Therefore, the dimensions of the rectangular vegetable patch are:

Length = 8 meters

Width = 6 meters

Dimensions: 8 × 6 meters.

3 0
3 years ago
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