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erastovalidia [21]
3 years ago
8

Homework: 6.2_HW

Mathematics
1 answer:
ra1l [238]3 years ago
3 0
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Answer:

a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.

b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.

Step-by-step explanation:

I am going to solve this question treating these events as Venn probabilities.

I am going to say that:

Event A: Person has type A blood.

Event B: Person has Rh- factor.

43% of people have type O blood

This means that P(A) = 0.43

15% of people have Rh- factor

This means that P(B) = 0.15

52% of people have type O or Rh- factor.

This means that P(A \cup B) = 0.52

a. Find the probability that a person has both type O blood and the Rh- factor.

This is

P(A \cap B) = P(A) + P(B) - P(A \cup B)

With what we have

P(A \cap B) = 0.43 + 0.15 - 0.52 = 0.06

0.06 = 6% probability that a person has both type O blood and the Rh- factor.

b. Find the probability that a person does NOT have both type O blood and the Rh- factor.

1 - 0.06 = 0.94

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