There are several ways you can solve this problem if you're trying to solve for m and n. You can substitute, or systems of equations. However, I'm going to use substitution:
2m + n = 0 => n = -2m
We can input that in for the other equation:
m + 2n = 3 now becomes: m + 2(-2m) = 3
Now we can solve:
m + 2(−2m) = 3
m + −4m = 3
(m + −4m) = 3 (Combine Like Terms)
−3m=3
m = -1
Now we can input that value in to solve for n:
We said that n = -2m, and m = -1, so n = -2(-1):Answer:
n = 2
Your final answer is m = -1, and n = 2, which can also be written as (m,n) = (-1,2)
----------------------
However, if you were solving for m+n:
You would add the two equations!:
2m + n = 0
m + 2n = 3
----------
3m + 3n = 3
Now, you can take 3 common:
3(m+n) = 3
m + n = 1
Your final answer for what m + n equals 1!
Answer:
maybe 2 only?
Step-by-step explanation:
I'm just guessing but it sounds right
Answer:it is only (x,y) -> (3x, 3y)
Step-by-step explanation: I just took the test and got it right,, hope it helped :)
Answer:
The probability that neither is available when needed
Step-by-step explanation:
A town has 2 fire engines operating independently
Given data the probability that a specific engine is available when needed is 0.96.
Let A and B are the two events of two fire engines
given P(A and B) = 0.96 ( given two engines are independent events so you have to select A and B)
Independent events : P( A n B) = P(A) P(B)
The probability that neither is available when needed
Answer:
168.61
Step-by-step explanation:
C=2*Pi*R
C=2*3.14*26.85
C=6.28*26.85
C=168.61
