What is the value of x 3 (x+2)=12
2 answers:
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Complete Question
The complete question is shown on the first uploaded image
Answer:
a
b
c
I would be surprised because the value is very small , less the 0.05
Step-by-step explanation:
From the question we are told that
The probability a randomly selected individual will not cover his or her mouth when sneezing is
Generally data collected from this study follows binomial distribution because the number of trials is finite , there are only two outcomes, (covering , and not covering mouth when sneezing ) , the trial are independent
Hence for a randomly selected variable X we have that
The probability distribution function for binomial distribution is
Considering question a
Generally the the probability that among 12 randomly observed individuals exactly 8 do not cover their mouth when sneezing is mathematically represented as
Here C denotes combination
So
Considering question b
Generally the probability that among 12 randomly observed individuals fewer than 5 do not cover their mouth when sneezing is mathematically represented as
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Considering question c
Generally the probability that fewer than half(6) covered their mouth when sneezing(i.e the probability the greater than half do not cover their mouth when sneezing) is mathematically represented as
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I would be surprised because the value is very small , less the 0.05
Answer with explanation:
→Number of Integers from 1 to 100
=100(50 Odd +50 Even)
→50 Even =2,4,6,8,10,12,14,16,...............................100
→50 Odd=1,3,,5,7,9,..................................99.
→Sum of Two even integers is even.
→Sum of two odd Integers is odd.
→Sum of an Odd and even Integer is Odd.
(a)
Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,
=Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,
=4900 ways
(b)
Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,
=Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,
=2500 ways