<span>p ← 1
s ← 0
for i is in {1, 2, 3, 4}
do p ← p · 3
s ← s + p
n = 1 => first iteration
p = 1 * 3 = 3
s = 0 + 3 = 3
number of multiplications ---> 1
n = 2
p = 3 * 3 = 9
s = 3 + 9 = 12
number of multiplications ----> 1 + 1 = 2
n = 3
p = 9 * 3 = 27
s = 12 + 27 = 39
number o multiplications --> 2 + 1 = 3
n = 4
p = 27 * 7 = 81
s = 39 + 81 = 120
final number of multiplications -----> 3 + 1 = 4
final value of s
s = 120
Answer: number of mujltiplications: 4
final value of s: s = 120.
</span>
Answer:
Step-by-step explanation:
Anything to the power of a negative number, means you are taking a reciprocal of the same result to a positive power.
For example:
Applying this same logic,
Answer:
hthtbhtnynnbnynynyn
Step-by-step explanaynyntion:
nynynynynynynynynynybfgbdfbe
