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TiliK225 [7]
3 years ago
13

Find the following for the function f(x) = x/x^2+1

Mathematics
1 answer:
7nadin3 [17]3 years ago
8 0

Step-by-step explanation:

step 1. f(0) = 0/(0^2 + 1) = 0/1 = 0

step 2. -f(x) = -x/(x^2 + 1)

step 3. f(9) = 9/(9^2 + 1) = 9/82.

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Which graph is the function. f(x)=x^3-3x^2-4x
Sedaia [141]

Answer:

See below description.

Step-by-step explanation:

The function f(x) = x^3-3x^2-4x has the following characteristics:

  • Factors: x(x+1)(x-4)
  • Zeros/roots: x=0, x=-1, amd x=4
  • Positive leading coefficient
  • Graph starts down and curves up through -1 on the x-axis and back down to cross through 0. It curves back up again through 4 and finished off heading into positive infinity.
  • Its graph is the shape of a sideways S.
  • It has a relative maximum at 1.128 and relative minimum value of -13.128

6 0
3 years ago
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WILL GIVE BRAINLIEST!! PLEASE HELP! <br> How do I factor 6v^2–36v+54 since 6 isn't a square root?
Elden [556K]

Answer:

6 (v-3)^2

Step-by-step explanation:

6v^2–36v+54

Factor out a 6

6(v^2–6v+9)

Then factor inside the parentheses

What 2 numbers multiply to 9 and add to -6

-3*-3 =9    -3+-3 = -6

6( v-3)(v-3)

6 (v-3)^2

4 0
3 years ago
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Can someone help plzzz
slava [35]
Z = 106
x = 32

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7 0
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If the initial velocity stays the same, but the height the projectile is launched from changes , how would the amount of time ch
pickupchik [31]

Answer:

Part A

The height to which the projectile reaches is given by the following formula;

\Delta y = y-y_0 = v_{0y} \times t-\dfrac{1}{2} \times g \times t^2

Where;

v_{0y} = The initial velocity of the projectile = Stays the same

y = The height the projectile reaches

y₀ = The height from which the projectile is launched

g = The acceleration due to gravity

t = The time taken

Given that the projectile has the same initial velocity, the variation of Δy with time, 't', will be the same when the project is launched from a different height, and the time change that it takes for the projectile to reach the maximum height will be the same for the previous launch height

Part B

From the change in eight of the projectile, Δy = y - y₀, the maximum height reached, 'y', is therefore given as follows;

y = Δy + y₀

The maximum height will increase by 'y₀', where 'y₀' is the difference between new height and the previous height, y_i

That is, if y₀ > y_i, the maximum height reached increases and if y₀ < y_i, y₀ will be added as y = Δy - y₀ and the maximum height reached decreases

Step-by-step explanation:

6 0
3 years ago
(yet the third) point giveaway.
Bas_tet [7]

Answer:

thank youuuuuuuu

Step-by-step explanation:

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