Ask question

Ask question

All categories

2 years ago

14

8th grade math, please help…

1 answer:

sergey [27]2 years ago

8 0

The measure of PMU is 56° and the measure of UPM is 62

You might be interested in

Which is the following equation rewritten in slope-intercept form: -8x=2-2y. A) y=1/4x+1. B) y=4x+1. C). Y=-4x+1. D) y=-4x-1

nevsk [136]

Step-by-step explanation:

-8x = 2 - 2y

2y - 8x = 2

2y = 8x + 2

y = 4x + 1

Answer B.

8 0

3 years ago

Read 2 more answers

a driver starts his parked car and within 5 seconds reaches a speed of 60km/h as he travels east. what is his acceleration

tatuchka [14]

$a = \tfrac{v}{t}$

$a = \tfrac{60km/hr}{5s}$

$a = \boxed{12 km/hr/s }$

Hope this helps :D

7 0

3 years ago

Read 2 more answers

A researcher is concerned about the impact of students working while they are enrolled in classes, and she likes to know if stud

8_murik_8 [283]

Answer:

(a) Point estimate = 7.10

(b) The critical value is 1.960

(c) Margin of error = 0.800

(d) Confidence Interval = (6.3, 7.9)

(e) We are 90% confident that the average number of hours worked by the students is between 6.3 and 7.9

Step-by-step explanation:

Given

$\bar x = 7.10$ -- sample mean

$\sigma=5$ --- sample standard deviation

$n = 150$ --- samples

Solving (a): The point estimate

The sample mean can be used as the point estimate.

Hence, the point estimate is 7.10

Solving (b): The critical value

We have:

$CI = 90\%$ --- the confidence interval

Calculate the $\alpha$ level

$\alpha = 1 - CI$

$\alpha = 1 - 90\%$

$\alpha = 1 - 0.90$

$\alpha = 0.10$

Divide by 2

$\frac{\alpha}{2} = 0.10/2$

$\frac{\alpha}{2} = 0.05$

Subtract from 1

$1 - \frac{\alpha}{2} = 1 - 0.05$

$1 - \frac{\alpha}{2} = 0.95$

From the z table. the critical value for $1 - \frac{\alpha}{2} = 0.95$ is:

$z = 1.960$

Solving (c): Margin of error

This is calculated as:

$E = z * \frac{\sigma}{\sqrt n}$

$E = 1.960 * \frac{5}{\sqrt {150}}$

$E = 1.960 * \frac{5}{12.25}$

$E = \frac{1.960 *5}{12.25}$

$E = \frac{9.80}{12.25}$

$E = 0.800$

Solving (d): The confidence interval

This is calculated as:

$CI = (\bar x - E, \bar x + E)$

$CI = (7.10 - 0.800, 7.10 + 0.800)$

$CI = (6.3, 7.9)$

Solving (d): The conclusion

We are 90% confident that the average number of hours worked by the students is between 6.3 and 7.9

6 0

3 years ago

Which line segments are a radius of Y?<br> RX<br> SW<br> SY<br> TY

Mumz [18]

Answer:RX SY TY please tell me if its wrong

5 0

3 years ago

Plz i need this rn

Lunna [17]

Answer:

well i feel like she walked the whole thing

because one tenth is 0.1 miles and she walked that distance

Step-by-step explanation:

4 0

3 years ago