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lana [24]
2 years ago
14

8th grade math, please help…

Mathematics
1 answer:
sergey [27]2 years ago
8 0
The measure of PMU is 56° and the measure of UPM is 62
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Plz help im bad at this type of math
aleksandrvk [35]
X + 14 + x + 14 = 17 + x + 7
2x + 28 = 24 + x
2x - x = 24 - 28
x = -4

DF = x + 14
= (-4) + 14
= 10
6 0
3 years ago
What is the value of 8 to the third power + 5x when x = 12
loris [4]
572 im pretty sure thats it
5 0
3 years ago
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Which equation shows a valid step in solving /2x-6+2x+6=0?
AfilCa [17]

An equation which shows a valid step that can be used to solve the given mathematical equation is (\sqrt[3]{2x - 6})^3 = (-\sqrt[3]{2x + 6})^3

<h3>What is an equation?</h3>

An equation simply refers to a mathematical expression that can be used to show the relationship existing between two (2) or more numerical quantities.

In this exercise, you're required to show a valid step which can be used to solve the given mathematical equation. Since both equations are having a cube root, the first step is to take the cube of both sides.

Take the cube of both sides, we have:

\sqrt[3]{2x - 6} + \sqrt[3]{2x + 6} = 0\\\\(\sqrt[3]{2x - 6})^3 + (\sqrt[3]{2x + 6})^3 = 0^3\\\\(\sqrt[3]{2x - 6})^3 = (-\sqrt[3]{2x + 6})^3

Read more on equations here: brainly.com/question/13170908

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5 0
2 years ago
Complete the passage to describe velocity vs time graphs.A velocity vs time graph is a graph that shows the relationship between
Fiesta28 [93]
1)Time is plotted on the x-axis in seconds
2)Velocity of the object is plotted on the y-axis in meters per second
4 0
4 years ago
Triangle J is shown below. James drew a scaled version of Triangle J using a scale factor of 4 and labeled it
Novay_Z [31]

Answer:

The area of triangle K is 16 times greater than the area of triangle J

Step-by-step explanation:

we know that

If Triangle K is a scaled version of Triangle J

then

Triangle K and Triangle J are similar

If two triangles are similar, then the ratio of its areas is equal to the scale factor squared

Let

z -----> the scale factor

Ak ------> the area of triangle K

Aj -----> the area of triangle J

so

z^{2}=\frac{Ak}{Aj}

we have

z=4

substitute

4^{2}=\frac{Ak}{Aj}

16=\frac{Ak}{Aj}

Ak=16Aj

therefore

The area of triangle K is 16 times greater than the area of triangle J

4 0
3 years ago
Read 2 more answers
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