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lana [24]
2 years ago
14

8th grade math, please help…

Mathematics
1 answer:
sergey [27]2 years ago
8 0
The measure of PMU is 56° and the measure of UPM is 62
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1/2 - 2/9 =<br><br>subtract. Simply if possible. ​
kozerog [31]

Answer:

\frac{5}{18}

Step-by-step explanation:

\frac{1}{2} -\frac{2}{9} =\frac{9}{18} -\frac{4}{18}=\frac{5}{18}

6 0
3 years ago
Read 2 more answers
Write an equation for the cubic polynomial function whose graph has zeroes at 2, 3, and 5.
TiliK225 [7]

we know that

For a polynomial, if x=a is a zero of the function, then (x−a) is a factor of the function. The term multiplicity, refers to the number of times that its associated factor appears in the polynomial.

So

In this problem

If the cubic polynomial function has zeroes at 2, 3, and 5

then

the factors are

(x-2)\\ (x-3)\\ (x-5)

Part a) Can any of the roots have multiplicity?

The answer is No

If a cubic polynomial function has three different zeroes

then

the multiplicity of each factor is one

For instance, the cubic polynomial function has the zeroes

x=2\\ x=3\\ x=5

each occurring once.

Part b) How can you find a function that has these roots?

To find the cubic polynomial function multiply the factors and equate to zero

so

(x-2)*(x-3)*(x-5)=0\\ (x^{2} -3x-2x+6)*(x-5)=0\\ (x^{2} -5x+6)*(x-5)=0\\ x^{3} -5x^{2} -5x^{2} +25x+6x-30=0\\ x^{3}-10x^{2} +31x-30=0

therefore

the answer Part b) is

the cubic polynomial function is equal to

x^{3}-10x^{2} +31x-30=0

7 0
3 years ago
Read 2 more answers
Solve for x, Show your work: 1/2 (16 - x) = -12 (x + 7)
soldi70 [24.7K]
You have to get rid of 1/2 by multiplying it by its recriprocal which is like this:
1) 1/2 x 2/1 which equals to zero and you do the same to the other side.
2) -12 x 2/1 = -24x then multiply-24x with 7 which equals -168.
16-x= -24x -168
3) subtract 16 to the other side and subtract 24x with x
23x= -184
4) divide by 23 to isolate x and you get -8
5) x=-8
6 0
3 years ago
Read 2 more answers
Question 1
Black_prince [1.1K]
C:x, in the bottom equation
4 0
2 years ago
The average daily volume of a computer stock in 2011 was million​ shares, according to a reliable source. A stock analyst believ
igomit [66]

Complete question :

The average daily volume of a computer stock in 2011 was p = 35.1 million shares, according to a reliable source. A stock analyst believes that the stock volume in 2014 is different from the 2011 level. Based on a random sample of 40 trading days in 2014, he finds the sample mean to be 30.9 million shares, with a standard deviation of s = 11.8 million shares. Test the hypotheses by constructing a 95% confidence interval. Complete parts (a) through (c) below. State the hypotheses for the test. Construct a 95% confidence interval about the sample mean of stocks traded in 2014.

Answer:

H0 : μ = 35.1 ;

H1 : μ < 35.1 ;

(26.488 ; 35.312)

Step-by-step explanation:

The hypothesis :

H0 : μ = 35.1

H1 : μ < 35.1

The confidence interval :

Xbar ± Margin of error

Xbar = 30.9

Margin of Error = Zcritical * s/sqrt(n)

Zcritical at 95% = 1.96

Margin of Error = 1.96 * (11.8/sqrt(40))

Margin of Error = 4.412

Lower boundary :

30.9 - 4.412 = 26.488

Upper boundary :

30.9 + 4.412 = 35.312

Confidence interval = (26.488 ; 35.312)

Since the population mean value exists within the interval, the we fail to reject the Null.

5 0
3 years ago
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