3.75.....rounded to the nearest dollar would be 4.00
Answer:
its c hope it helps not totally sure but yeah
Step-by-step explanation:
Answer:
Null Hypothesis: H_0: \mu_A =\mu _B or \mu_A -\mu _B=0
Alternate Hypothesis: H_1: \mu_A >\mu _B or \mu_A -\mu _B>0
Here to test Fertilizer A height is greater than Fertilizer B
Two Sample T Test:
t=\frac{X_1-X_2}{\sqrt{S_p^2(1/n_1+1/n_2)}}
Where S_p^2=\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}
S_p^2=\frac{(14)0.25^2+(12)0.2^2}{15+13-2}= 0.0521154
t=\frac{12.92-12.63}{\sqrt{0.0521154(1/15+1/13)}}= 3.3524
P value for Test Statistic of P(3.3524,26) = 0.0012
df = n1+n2-2 = 26
Critical value of P : t_{0.025,26}=2.05553
We can conclude that Test statistic is significant. Sufficient evidence to prove that we can Reject Null hypothesis and can say Fertilizer A is greater than Fertilizer B.
<u>Complete Question:</u>
Corinne is taking a train into the city. The train travels at a rate of 45 miles per hour. Which quantity depends on the other?
A. The distance traveled depends on the number of hours traveled.
B. The number of hours traveled depends on the speed of the train.
C. The speed of the train depends on the distance traveled.
D. The speed of the train depends on the number of hours traveled.
<u>Answer:</u>
Corinne is taking a train into the city. The train travels at a rate of 45 miles per hour. The distance traveled depends on the number of hours traveled
<u>Step-by-step explanation:</u>
As we know the velocity can de defined as the rate of change of position of objects in a particular time. The formula is given by,

Here, in the question, rate of speed of train is given as 45 miles per hour. if we keep the velocity as constant one, then distance is directly proportionate to the travelled time

If 'v' is constant,

By this we can conclude that, the distance travelled by the train depends on the time taken to travel to it. Hence option A would be the correct one.
Answer:
It will take her 75 minutes To run 10 miles.
Step-by-step explanation:
I believe to run 10 miles (not minutes)
30/4= 7.5 minute per mile
7.5*10= 75 minutes