Simplify<br> 53<br> Enter your answer in the box

I need help on this plZ

never [62]

Answer:

1. See the attached figure to this answer.

2. Lines A and B are parallel to each other.

3. Line Z is the transversal.

4. The same side interior angles are ∠ 4, ∠ 6 & ∠ 3, ∠ 5.

5. The alternate interior angles are ∠ 3, ∠ 6 & ∠ 4, ∠5

6. Corresponding angles are ∠ 1, ∠ 6 & ∠ 2, ∠ 5 & ∠ 3, ∠ 7 & ∠ 4, ∠ 8.

7. Alternate interior angles are ∠ 4, ∠ 5 & ∠ 3, ∠ 6 (Answer)

Step-by-step explanation:

1. See the attached figure to this answer.

2. Lines A and B are parallel to each other.

3. Line Z is the transversal.

4. The same side interior angles are ∠ 4, ∠ 6 & ∠ 3, ∠ 5.

5. The alternate interior angles are ∠ 3, ∠ 6 & ∠ 4, ∠5

6. Corresponding angles are ∠ 1, ∠ 6 & ∠ 2, ∠ 5 & ∠ 3, ∠ 7 & ∠ 4, ∠ 8.

7. Alternate interior angles are ∠ 4, ∠ 5 & ∠ 3, ∠ 6 (Answer)

7 0

3 years ago

Read 2 more answers

Priya drew a circle whose area is 25 cm. Dan drew a circle whose diameter is 4 times the radius of Priya's circle. How many time

Vitek1552 [10]

Answer:

400

Step-by-step explanation:

first work out the radius of priya's circle with the equation a = $\pi r^{2}$

$25 = \pi r^{2}$

$\frac{25}{\pi } = r^{2}$

$r = \sqrt{\frac{25}{\pi } }$

we know the diameter of a circle is 2 times the radius so the diameter of priya's circle is 2x $\sqrt{\frac{25}{\pi } }$

this means that if the diameter of dan's circle is 4 times bigger it must be

8x $\sqrt{\frac{25}{\pi } }$

to find the radius of dan's circle we divide the diameter by to 2 to give

4x $\sqrt{\frac{25}{\pi } }$

then use the a= $\pi r^{2}$ equation again

$a= (4 \sqrt{\frac{25}{\pi } })^{2} \pi$

which equals 400

hope that helped

6 0

3 years ago

Let Y be a random variable with a density function given by

Neporo4naja [7]

From the given density function we find the distribution function,

$F_Y(y)=P(Y\le y)=\displaystyle\int_{-\infty}^y f_Y(t)\,\mathrm dt=\begin{cases}0&\text{for }y$

(a)

$F_{U_1}(u_1)=P(U_1\le u_1)=P(3Y\le u_1)=P\left(Y\le\dfrac{u_1}3\right)=F_Y\left(\dfrac{u_1}3\right)$

$\implies F_{U_1}(u_1)=\begin{cases}0&\text{for }u_1$

$\implies f_{U_1}(u_1)=\begin{cases}\frac{{u_1}^2}{18}&\text{for }-3\le u_1\le3\\0&\text{otherwise}\end{cases}$

(b)

$F_{U_2}(u_2)=P(3-Y\le u_2)=P(Y\ge3-u_2)=1-P(Y$

$\implies F_{U_2}(u_2)=\begin{cases}0&\text{for }u_2$

$\implies f_{U_2}(u_2)=\begin{cases}\frac32(u_2-3)^2&\text{for }2\le u_2\le4\\0&\text{otherwise}\end{cases}$

(c)

$F_{U_3}(u_3)=P(Y^2\le u_3)=P(-\sqrt{u_3}\le Y\le\sqrt{u_3})=F_Y(\sqrt{u_3})-F_y(\sqrt{u_3})$

$\implies F_{U_3}(u_3)=\begin{cases}0&\text{for }u_3$

$\implies f_{U_3}(u_3}=\begin{cases}\frac32\sqrt u&\text{for }0\le u\le1\\0&\text{otherwise}\end{cases}$

5 0

3 years ago

Swimming pool, only certain hot summers day, 430 People used the public swimming pool. The daily prices are $1.50 for children a

Leona [35]

Answer:

Step-by-step explanation:

The question doesn't make sense. There is no way receipts could have totaled $8008.50. The most that could have been taken is if all 430 of the patrons were adults. That gives 430×2.25 = $967.50

3 0

2 years ago

A rectangular prism has a length of 3/4 cubic inch and a width of 1/2 inch. The volume is 21/32 cubic inch. Find the height of t

Oliga [24]

21 / 32 = (3/4) * (1/2) * height

21 / 32 = (3 / 8) * height

21 / 32 * (3 / 8) = height =

63 / 256 inches

7 0

3 years ago

Read 2 more answers

Simplify 53 Enter your answer in the box