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noname [10]
2 years ago
13

arcus had 8/9 of a pack of construction paper. he used 1/5 of the paper to make paper airplanes. what fraction of the original p

ack did Arcus use to make paper airplanes?
Mathematics
1 answer:
vovikov84 [41]2 years ago
4 0
Take and do 8/9 - 1/5 which gives u 40/9which equals 4 4/9.
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What is the answer for 5.2 × 10-9 + 3.1 × 10-8 = × 10?
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Subtract x^10 from both sides. add 17 to both sides. divide both sides by 7.3 take root and the answer should be x=1.08821, -1.08821
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Please help, this is from ANNOYING Khan Academy.
GalinKa [24]

Answer:

-20

Step-by-step explanation:

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2 years ago
The black figure is an ellipse, and the black line segment is is major axis. What is the length of the blue line segment?
NeTakaya

Answer:

D

Step-by-step explanation:

The formula we need to solve this is:

d_1+d_2=2a

Where

d_1  is the distance from one focus to the vertex

d_2  is the second distance from another focus to same vertex

<u>Note:</u> Here, vertex point is the point on top. The common point from which the RED and BLUE line meets the 2 foci

a  is half the length of the major axis (which is 9 here since total major axis is given as 18)

<em>Now we can plug into the equation and solve:</em>

<em>d_1+d_2=2a\\8.5+d_2=2(9)\\8.5+d_2=18\\d_2=18-8.5\\d_2=9.5</em>

<em />

<em>D is the correct answer.</em>

6 0
3 years ago
A rolling pin has two identical cylindrical handles attached to a larger handle that is 12 inches long. The large cylinder measu
yaroslaw [1]

Answer:

Volume of the rolling pin =  246.09 in^{3}  

Step-by-step explanation:

Length of larger cylinder L = 12 in

Diameter of larger cylinder D = 5 in

Diameter of two handles = 1.5 in

Length of two handles = 3 in

Volume of the rolling pin = Volume of two handles + Volume of larger cylinder

Volume of two handles = 2 (\pi r^{2}L)

Volume of two handles =  2 (3.14 × 0.75^{2} × 3 )

Volume of two handles = 10.59 in^{3}  

Volume of larger cylinder = (\pi r^{2}L)

Volume of larger cylinder = (3.14 × 2.5^{2} × 12 )

Volume of larger cylinder = 235.5 in^{3}  

Volume of the rolling pin =  10.59 + 235.5

Volume of the rolling pin =  246.09 in^{3}  

6 0
2 years ago
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