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irina [24]
3 years ago
13

Can anyone give me a solution in Divisibility Rules (Any rules except for divisibility rule by 7), Thank you

Mathematics
1 answer:
jeka57 [31]3 years ago
3 0

Answer:

1 = Any number

2 = Any even number

3 = Sum of digits is divisible by 3

4 = Last two digits are divisible by 4

5 = Ends in 5 or 0

6 = Divisible by 2 and 3

8 = Last three digits are divisible by 8

9 = Sum of digits are divisible by 9

10 = Ends in 0

Step-by-step explanation: It's just how it is. Please mark as Brainliest! :D

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GJ bisects ∠FGH and is a perpendicular bisector of FH.
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Solution:

In \Delta FGH, As, given G J bisects ∠F G H and is a perpendicular bisector of F H.

So, F J=J H →→ G J is a perpendicular bisector of F H.

We will use angle bisector theorem to determine which statement is correct.

As, Angle bisector theorem states that , if a line segment bisects an angle, then the ratio of sides adjacent to angle, is equal to the ratio of two segments where the angle bisector cuts the third side.

So, \frac{GH}{GF}=\frac{HJ}{JF}\\\\ \frac{GH}{GF}=1\\\\ GH=GF

The option (C) which is the  \Delta F G H has exactly 2 congruent sides is true.

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3 years ago
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3 years ago
pings ice cream palace offers a special sunday that contains 2 kilograms of ice cream plus any number of toppings. Write an S, t
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Let us assume number of toppings = n

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Quantity of Ice cream = 2 kilograms.

We need to discribe the total weight of the special sundae in kilograms by an inequality.

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Therefore,

The total weight of the sundae > total weight of ice cream + weight of toppings.

s > 2 + n.

Where, s is the total weight of the sundae and n is the weight of toppings.

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Answer:

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