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Nuetrik [128]
2 years ago
5

There are 738 students going on a school field trip. Each bus can carry 33 students. How many buses should the school reserve? b

uses
Mathematics
2 answers:
creativ13 [48]2 years ago
6 0
It would be 23 I think.

BRAINLIEST PLEASE
lukranit [14]2 years ago
5 0

Answer:

23 buses should be reserved

Step-by-step explanation:

23 should be reserved because if there are 738 students going on a field trip and each bus can only hold 33 students then they will require many buses (Wow, that's a lot of students...) Ok so first of all to find how many buses we need, we need to divide 738 by 33

738/33 = 22.3636363636

but since students and buses can't be split in half (without causing harm at least) we need to round it, once rounded we are left with 22 buses but where do the rest of the students go? That's why we have to bump 22 up by 1 giving us 23, therefore allowing all the students to come, Thus your only viable solution is 23!

Hope this Helps!

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QUICKLY HELP! Which relationship between x and y in the equation shows a proportional relationship?
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Drag the tiles to list the sides of △MNO from shortest to longest.
sweet [91]

The smaller the angle subtended by a side, the smaller the length of the

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The correct responses are;

Question 1: The list of sides from shortest to longest are;

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a) <u>Friday</u>

b) <u>70 minutes</u>

c) <u>40%</u>

d) Yes<u>,</u> <u>the sum of the </u><u>mean</u><u> number of </u><u>minutes spent</u><u> on </u><u>aerobic</u><u> training and the mean number of minutes spent on </u><u>strength</u><u> training is equal to the mean </u><u>total</u><u> number of minutes spent </u><u>training.</u>

From the given diagram, we have, the measure of the third angle, ∠O, is

found as follows;

∠O = 180° - 54° - 61° = 65°

Therefore, ∠O = The largest angle

We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= \frac{}{MO}

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The longest side is the side opposite ∠O(65°) = \frac{}{MN}

a) The time spent training on Tuesday = 60 + 10 = 70 minutes

The time spent training on Thursday = 50 + 30 = 80 minutes

The time spent training on Friday = 45 + 40 = 85 minutes

Therefore, the day the athlete spent the longest total amount of time training is on <u>Friday</u>

b) The time spent training on Monday = 10 + 20 = 30 minutes

The time spent training on Wednesday = 20 + 15 = 35 minutes

Therefore, we get;

30, 35, 70, 80, and 85

The median total number of minutes the athlete spent training each day = <u>70 minutes</u>

<u />

c) The time spent strength training = 20 + 10 + 15 + 30 + 45 = 120

The total number of minutes the athlete spent training = 70 + 80 + 85 + 30 + 35 = 300

The  percentage spent on strength training = \frac{120}{300} × 100 = \frac{40}%

d) The mean number of minutes spent on strength training is found as follows;

Mean_{strength} =\frac{120}{5} =24

The mean number of minutes spent on aerobic training is found as follows;

Mean_{aerobic} =\frac{10+60+20+50+40}{5} =36

Mean_{strength} +Mean_{aerobic} =24+36=60

The mean total number of minutes spent training, Mean_{total} = \frac{300}{5} = 60

Therefore;

  • Mean_{strength}+Mean_{aerobic} = Mean_{total} \\

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2 years ago
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Robin, who is self-employed, contributes $4500/year into a Keogh account. How much will he have in the account after 30 years if
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Answer:

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Step-by-step explanation:

Here, we want to calculate the amount that will be present in the account after 30 years if the interest is compounded yearly

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A = [P(1 + r)^t-1]/r

From the question;

P is the amount deposited yearly which is $4,500

r is the interest rate = 2.5% = 2.5/100 = 0.025

t is the number of years which is 30

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A = [4500(1 + 0.025)^30-1]/0.025

A = [4500(1.025)^29]/0.025

A = 368,353.3309607034

To the nearest whole dollars, this is;

$368,353

4 0
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