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natali 33 [55]
3 years ago
15

Use Structure A line passes through points Aln, 4) and B(6, 8) and is parallel to y = 2x - 5. What is the value of n?

Mathematics
1 answer:
artcher [175]3 years ago
8 0

Step-by-step explanation:

From y=2x-5, gradient=2

<u>C</u><u>h</u><u>a</u><u>n</u><u>g</u><u>e</u><u> </u><u>i</u><u>n</u><u> </u><u>y</u><u> </u>= Gradient

Change in x

<u>8</u><u>-</u><u>4</u><u> </u>=2

6-n

4 = 2(6-n)

4 =12 -2n

4 - 12 = -2n

-8 = -2n

<u>-</u><u>8</u> =n

-2

n= 4

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the function of y= x^2 - 4x + 8 approximates the height y, of a bird and its horizontal distance, x as it flies from one fence p
Vika [28.1K]
Rewrite the given equation as 
y=x^2-4x+8=x^2-4x+4+4=(x-2)^2+4.
Since (x-2)^2\ge 0, you can conclude that the imimum value of y will be gained for the minimum value of (x-2)^2. The minimum value of (x-2)^2 is 0 for x=2. 
So, y(2)=0+4=4.
Answer: minimum value of y is 4, when x=2.


7 0
3 years ago
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winnie and kevin like to create their own triathlon courses to challenge each other. last weekend, winnie created a course that
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Answer: the answer is 121/4

Step-by-step explanation:

8 0
3 years ago
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Answer:

$41.0625

Step-by-step explanation:

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Multiply the answer to that (13.6875) by 3 or subtract 054.5 by 13.6873

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8 0
3 years ago
In hypothesis testing, if the null hypothesis has been rejected when the alternative hypothesis has been true, _____. a. a Type
lara31 [8.8K]

Answer:(c)

Step-by-step explanation:

Given : In a hypothesis testing the null hypothesis has been rejected when the alternative hypothesis has been true.

Find : to find that the given decision is create type I error , type II error or right decision has been taken

Step by step :

In hypothesis testing there are 2 types of error.

(1)Type I error :- if the null hypothesis is rejected when it is true, is known has Type I error .

(2)Type II error:- if the null hypothesis is accepted when alternative hypothesis is true, is known as type II error.

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4 0
3 years ago
What is the equation of the circle with center (2, –5) that passes through the point (–2, 10)?
Travka [436]
The standard equation of a circle is

(x-h)^2 + (y-k)^2 = r^2

where the center is at point (h,k)

From the statement of the problem, it is already established that h = 2 and k = -5. What we have to determine is the value of r. This could be calculated by calculating the distance between the center and point (-2,10). The formula would be

r = square root [(x1-x2)^2 + (y1-y2)^2)]
r = square root [(2--2)^2 + (-5-10)^2)]
r = square root (241)
r^2 = 241

Thus, the equation of the circle is

(x-2)^{2} + (y+5)^{2} =241
4 0
3 years ago
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