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3 years ago

Draw arrays and a factor rainbow to find all of the factor pairs for the number 16

Mathematics

1 answer:

KATRIN_1 [288]3 years ago

3 0

Answer:

the factors of 16 are

1 * 16 = 16

2 * 8 = 16

4 * 4 = 16

Step-by-step explanation:

to find the factor pairs of a number you have to find the multiples of that number meaning what times what equals that number

formula for factor pairs: x * x = A

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After all markdowns and discounts, Charlene's prom dress cost her $22 before tax. The dress was on a rack labeled "50% off lowes

uysha [10]

Answer: $88.

Step-by-step explanation:

given data:

The cost of the dress for the prom = $22

label of the rack the dresss was on = 50%.

lowest marked price for the dress = 75%.

Solution:

if the lowest marked price of the cloth was already 75%.

and the current cost of the clothe is $22

the original cost of the cloth would be

100% – 75% = 0.25%

= $22 * 100 / 0.25%

= $88.

The original cost of the dress was $88

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4 years ago

What are the factors of x2 – 4x – 5? Check all that apply.

harkovskaia [24]

When you factor (x^2-4x-5), you get (x+1)(x-5).

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3 years ago

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You earn $9.20 per hour at your summer job. Identify an inequality that represents the number p of hours you need to work in ord

Korvikt [17]

Answer:

$32.5

Step-by-step explanation:

I hope this helps.

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3 years ago

Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.

Mice21 [21]

Answer:

LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

Step-by-step explanation:

Making factors of $8y^{6}+ 144y^{5}+ 640y^{4}$

Taking $8y^{4}$ common:

$\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)$

Using factorization method:

$\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)$

Now, Making factors of $2y^{4} + 40y^{3} + 200y^{2}$

Taking $2y^{2}$ common:

$\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)$

Using factorization method:

$\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)$

The underlined parts show the Highest Common Factor(HCF).

i.e. HCF is $2y^{2} (y+ 10)$ .

We know the relation between LCM, HCF of the two numbers 'p' , 'q' and the numbers themselves as:

$HCF \times LCM = p \times q$

Using equations (1) and (2): $\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)$

Hence, LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

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3 years ago

Please help, I'll mark Brainiest. It's 8th grade math

yawa3891 [41]

Answer:

(-5, 2)

Step-by-step explanation:

plug x into the equation x - 5y = -15

-5 - 5y = -15

add 5 to both sides: -5y = -10

divide by -5: y = 2

7 0

3 years ago

Read 2 more answers