This is an incomplete question, here is a complete question and image is also attached below.
How much longer is the hypotenuse of the triangle than its shorter leg?
a. 2 ft
b. 4 ft
c. 8 ft
d. 10 ft
Answer : The correct option is, (b) 4 ft
Step-by-step explanation:
Using Pythagoras theorem in ΔACB :
Given:
Side AC = 6 ft
Side BC = 8 ft
Now put all the values in the above expression, we get the value of side AB.
Now we have to calculate the how much longer is the hypotenuse of the triangle than its shorter leg.
Difference = Side AB - Side AC
Difference = 10 ft - 6 ft
Difference = 4 ft
Therefore, the 4 ft longer is the hypotenuse of the triangle than its shorter leg.
To calculate circumference, you must use the equation (65)(2)(Pi) which would be 408.2pm. (IF YOU COUNT PI AS 3.14)
Answer:
(4,1)
Step-by-step explanation:
Reflected over x = -3, new point : (1,4)
Reflected over y=x, new point = (4,1)
Answer:
x = 32
m∠7 = 94
m∠8 = 86
m∠3 = 94
Step-by-step explanation:
(2x + 30) + (3x - 10) = 180
5x + 20 = 180
5x = 160
x = 32
m∠7 = 2(32) + 30 = 94
m∠8 = 3(32) - 10 = 86
<u>or</u>
m∠8 = 180 - 94 = 86
<u>m∠3 ≈ m∠7</u> (corresponding angles)
Answer:
(0, 11) is a solution.
(8, 12) is a solution.
(16, 13) is a solution
(1, 89/8)
(2, 45/4)
Step-by-step explanation:
y = 1/8x + 11
for this equation....
y = (1/8) x + 11
let x = 0 get
y = 0 + 11 = 11
(0, 11) is a solution.
(8, 12) is a solution.
(16, 13) is a solution
(1, 89/8) because y = 1/8 + 11 = 1/8 + 88/8 = 89/8
(2, 45/4)
