Answer:
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Step-by-step explanation:
Given that;
the frequencies of there alternatives are;
Frequency A = 60
Frequency B = 12
Frequency C = 48
Total = 60 + 12 + 48 = 120
Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;
Relative Frequency A = Frequency A / total = 60 / 120 = 0.5
Relative Frequency B = Frequency B / total = 12 / 120 = 0.1
Relative Frequency C = Frequency C / total = 48 / 120 = 0.4
therefore;
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Answer:
24
Step-by-step explanation:
x-3=5, solve for x so that x=5+3
now put this in place of x in the expression 2(x+4)
2[(5+3)+4]
2(8+4)
2(12)
24
Answer:
6.966
Step-by-step explanation:
•Mark how many you have in the d.p
•If there is two or more add them up
•Multiply like normal given numbers
•Write where the decimal point is to be
Hope that helps
Hi i a doing the same thing and i have the answer as a hope this helps
Answer: 8.29 still...
Step-by-step explanation:
When your doing the nearest hundreth, the thousandth has to be close to 10 to make it a diffrent number, if it WAS, then it would be 8.30
