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xxTIMURxx [149]
3 years ago
6

Rationalize the denominator 1/√3−1

Mathematics
2 answers:
Effectus [21]3 years ago
8 0
<h3><u>Solution</u><u>:</u></h3>

<u>\frac{1}{ \sqrt{3} - 1 }  \\  =  \frac{1}{ \sqrt{3}  - 1}  \times  \frac{ \sqrt{3}  + 1}{ \sqrt{3} + 1 }  \\  =   \frac{ \sqrt{3}  + 1}{( \sqrt{3})^{2}  - (1)^{2}  }  \\  =    \frac{ \sqrt{3} + 1 }{3 - 1}  \\  =   \frac{ \sqrt{3}  + 1}{2}</u>

<h3><u>Answer</u><u>:</u></h3>

<u>\frac{ \sqrt{3}  + 1}{2}</u>

dem82 [27]3 years ago
6 0
Multiply the fraction by the (denominator/denominator)
Which is equals to 1.

1/root3-1 * (1/root3-1) / (1/root3-1)

Now you have root3-1 / 2
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astra-53 [7]

Answer: c = 520

Step-by-step explanation:

     f(2) = 578 means that when x = 2, the value is equal to 578. We will plug these knowns in and then solve for c.

Given:

    f(x) = 4x³ + 7x² - x + c

Substitute:

    578 = 4(2)³ + 7(2)² - (2) + c

Distribute:

    578 = 4 * 2³ + 7 * 2² - 2 + c

Raise to the power of 3 and 2:

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Add:

    578 = 60 - 2 + c

Subtract:

    578 = 58 + c

Subtract 58 from both sides:

    520 = c

Reflexive property:

   c = 520

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Natalija [7]

Answer:

5.831

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3^2+5^2= 34

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Answer:

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Step-by-step explanation:

19-2 = 17

17 x 180 = 3060

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