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makkiz [27]
3 years ago
10

How to calculate percentage increase

Mathematics
1 answer:
joja [24]3 years ago
8 0
Work out the difference (increase<span>) between the two numbers you are comparing. Then divide the </span>increase<span> by the original number and multiply the answer by 100. If your answer is a negative number then this is a </span>percentage <span>decrease.</span>
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Round 3,989.23655 to the nearest thousandth
inysia [295]
3,989.237
A thousandth = 1/1000 = 0.001
Round 4th decimal place = 5
5 and over is rounding up and under 5 rounds down so it would be 3,989.237
6 0
3 years ago
A kite flying in the air has a 12 line attached to it. Its line is pulled taut and casts a 9 shadow. Find the height of the kite
alexira [117]

Answer:

8 (7.94)

Step-by-step explanation:

You can think of it as a geometry problem.

What is formed here is a triangle, which sides ate: the line, the line's shadow, and the height from the ground to the kite (here I attach a drawing).

What you need to find is the height. We will call it H.

As the triangle formed is a right one, we can use Pitágoras' theorem. The height H squared plus the squared of the shadow is equal to the squared of the line (the hypotenuse). This is:

H^2 + 9^2 = 12^2

H^2 + 81= 144

H^2 = 63

Applying squared root in both sides

H = √63

H = 7,94

So, the height is approximately 8.

4 0
3 years ago
the numbers 1,2,3,4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacet. find t
Tresset [83]

Consider such events:

A - slip with number 3 is chosen;

B - the sum of numbers is 4.

You have to count Pr(A|B).

Use formula for conditional probability:

Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)}.

1. The event A\cap B consists in selecting two slips, first is 3 and second should be 1, because the sum is 4. The number of favorable outcomes is exactly 1 and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event A\cap B is

Pr(A\cap B)=\dfrac{1}{20}.

2. The event B consists in selecting two slips with the sum 4. The number of favorable outcomes is exactly 2 (1st slip 3 and 2nd slip 1 or 1st slip 1 and 2nd slip 3) and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event B is

Pr(B)=\dfrac{2}{20}=\dfrac{1}{10}.

3. Then

Pr(A|B)=\dfrac{\frac{1}{20} }{\frac{1}{10} }=\dfrac{1}{2}.

Answer: \dfrac{1}{2}.

5 0
3 years ago
Decrease £2123 by 8%
Gemiola [76]
Should be £1953.16 :)
3 0
2 years ago
Rewrite the expression as the sum of two numbers<br> 3(1+3)
Alja [10]

Answer:

3 + 9

Step-by-step explanation:

Distribute the 3 to both numbers, so 3 x 1 = 3, and 3 x 3 = 9.

5 0
2 years ago
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