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erastova [34]
3 years ago
11

in the three stacks of books there are 15 books, 9 books and 9 books if the books were rearranged so that the stack had the same

number of books how many books would be even?​
Mathematics
1 answer:
zepelin [54]3 years ago
3 0

Answer:

<u>There would be 11 books in each stack, to have the same number.</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Books in stack 1 = 15

Books in stack 2 = 9

Books in stack 3 = 9

2.  If the books were rearranged so that the stack had the same number of books how many books would be even?​

Total books = Books in stack 1 + Books in stack 2 + Books in stack 3

Total books = 15 + 9 + 9

Total books = 33

Total books/Number of stacks = Number of books per stack to be the same

33/3 = Number of books per stack to be the same

<u>Number of books per stack to be the same = 11</u>

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Answer:

From least to greatest, the order would go: 2.207, 2.27, 2.9, 3.76.

Step-by-step explanation:

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Hope this helps! :)

7 0
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If the expression $3^1 times 9^2 times 27^3 \times 81^4 is simplified to the form 3^n, what is the value of n?
Darina [25.2K]

Answer:

n=30

Step-by-step explanation:

Given expression:

3^1\times 9^2\times 27^3\times 81^4

The given expression needs to be simplified to the form 3^n

Applying the exponents rule to simplify.

3^1\times 9^2\times 27^3\times 81^4

Writing all numbers as product of 3.

⇒ 3^1\times (3\times3)^2\times (3\times3\times3)^3\times (3\times3\times3\times3)^4

Writing each in exponents form.

⇒ 3^1\times (3^2)^2\times (3^3)^3\times (3^4)^4

Using power of a power rule [\ (a^x)^y=a^{xy}\ ]

⇒ 3^1\times 3^4\times 3^9\times 3^16

Using multiplication rule of exponents [\ a^x\times a^y=a^{x+y}\ ]

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So we have 3^n=3^{30}

∴ n=30

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