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Misha Larkins [42]
3 years ago
11

Which one A, B, C, or D

Mathematics
2 answers:
rjkz [21]3 years ago
8 0

Answer:

The answer would be A

____ [38]3 years ago
5 0

Answer:

i tthink it would be a

Step-by-step explanation:

You might be interested in
You will write a 5-paragraph essay explaining how you would solve the following equation:
sattari [20]

Answer:

x=0

Step-by-step explanation:

\frac{7}{3}(2x+3)+\frac{3}{4}(\frac{x}{5}-\frac{15}{2})=\frac{11}{8} <-- Given

\frac{14}{3}x+7+\frac{3}{20}x-\frac{45}{8}=\frac{11}{8} <-- Distributive Property

\frac{280}{60}x+7+\frac{9}{60}x-\frac{45}{8}=\frac{11}{8} <-- Find LCD of x-terms

\frac{289}{60}x+7-\frac{45}{8}=\frac{11}{8} <-- Combine Like Terms

\frac{289}{60}x+7=\frac{56}{8} <-- Add 45/8 to both sides

\frac{289}{60}x+7}=7 <-- Simplify Right Side

\frac{289}{60}x=0 <-- Subtract 7 on both sides

x=0 <-- Divide both sides by 289/60

3 0
2 years ago
a local hamburger shop sold a combined total of 616 hamburgers and cheeseburgers on sunday. there were 66 moore cheeseburgers so
Ksju [112]

Answer:

242 Hamburgers,  374 Cheeseburgers

Step-by-step explanation:

Step 1: 616/2-66=242 Hamburgers

Step 2: 616-242=374 Cheeseburgers

Step 3: Check Work 242+374=616

4 0
3 years ago
In a random sample of 300 attendees of a minor league baseball game, 182 said that they bought food from the concession stand. C
horrorfan [7]

Answer:

<em>90% confidence interval for the proportion of fans who bought food from the concession stand</em>

(0.5603,0.6529)

Step-by-step explanation:

<em>Step(i)</em>:-

<em>Given sample size 'n' =300</em>

Given data  random sample of 300 attendees of a minor league baseball game, 182 said that they bought food from the concession stand.

<em>Given sample proportion </em>

<em>                        </em>p^{-}  = \frac{x}{n} = \frac{182}{300} =0.606

level of significance = 90% or 0.10

Z₀.₁₀ = 1.645

<em>90% confidence interval for the proportion is determined by</em>

(p^{-} - Z_{0.10}\sqrt{\frac{p(1-p)}{n} }  , p^{-} +Z_{0.10}\sqrt{\frac{p(1-p)}{n} })

(0.6066 - 1.645\sqrt{\frac{0.6066(1-0.6066)}{300} }  ,0.6066+1.645\sqrt{\frac{0.6066(1-0.6066)}{300} })

(0.6066 -  0.0463  ,0.6066 +  0.0463)

(0.5603,0.6529)

<u>final answer</u>:-

<em>90% confidence interval for the proportion of fans who bought food from the concession stand</em>

(0.5603,0.6529)

5 0
3 years ago
What is the solution?
AfilCa [17]

Answer:

A

Step-by-step explanation:

4 0
2 years ago
I WILL GIVE BRAINLIEST TO CORRECT ANSWER
Svet_ta [14]
180 students have a pet
3 0
2 years ago
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