we have
![4x^5-12x^4+6x=5x^3-2x](https://tex.z-dn.net/?f=%204x%5E5-12x%5E4%2B6x%3D5x%5E3-2x%20)
Separate the equation above in two equations
equation ![1](https://tex.z-dn.net/?f=%201%20)
![y=4x^5-12x^4+6x](https://tex.z-dn.net/?f=%20y%3D4x%5E5-12x%5E4%2B6x%20)
equation ![2](https://tex.z-dn.net/?f=%202%20)
![y=5x^3-2x](https://tex.z-dn.net/?f=%20y%3D5x%5E3-2x%20)
we know that
In a system of equations the roots of the equation
must satisfy equation
and the roots of the equation
must satisfy equation ![1](https://tex.z-dn.net/?f=%201%20)
therefore
the answer is
The system of equations is
![y=4x^5-12x^4+6x](https://tex.z-dn.net/?f=%20y%3D4x%5E5-12x%5E4%2B6x%20)
![y=5x^3-2x](https://tex.z-dn.net/?f=%20y%3D5x%5E3-2x%20)
Answer:
$3.75
Step-by-step explanation:
This is the answer! Just trust me!
Answer:
![P =0.3998](https://tex.z-dn.net/?f=P%20%3D0.3998)
Step-by-step explanation:
Let
be the average of the sample, and the population mean will be
We know that:
gr
Let
be the standard deviation and n the sample size, then we know that the standard error of the sample is:
![E=\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
Where
![\sigma=569](https://tex.z-dn.net/?f=%5Csigma%3D569)
![n=130](https://tex.z-dn.net/?f=n%3D130)
In this case we are looking for:
![P(|{\displaystyle{\overline{x}}}- \mu|>42)](https://tex.z-dn.net/?f=P%28%7C%7B%5Cdisplaystyle%7B%5Coverline%7Bx%7D%7D%7D-%20%5Cmu%7C%3E42%29)
This is:
or ![{\displaystyle{\overline{x}}}- \mu](https://tex.z-dn.net/?f=%7B%5Cdisplaystyle%7B%5Coverline%7Bx%7D%7D%7D-%20%5Cmu%3C-42)
![P=P({\displaystyle{\overline{x}}}- \mu>42)+ P({\displaystyle{\overline{x}}}- \mu](https://tex.z-dn.net/?f=P%3DP%28%7B%5Cdisplaystyle%7B%5Coverline%7Bx%7D%7D%7D-%20%5Cmu%3E42%29%2B%20P%28%7B%5Cdisplaystyle%7B%5Coverline%7Bx%7D%7D%7D-%20%5Cmu%3C-42%29)
Now we get the z score
![Z=\frac{{\displaystyle{\overline{x}}}-\mu}{\frac{\sigma}{\sqrt{n}}}](https://tex.z-dn.net/?f=Z%3D%5Cfrac%7B%7B%5Cdisplaystyle%7B%5Coverline%7Bx%7D%7D%7D-%5Cmu%7D%7B%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D)
![P=P(z>\frac{42}{\frac{569}{\sqrt{130}}}) + P(z](https://tex.z-dn.net/?f=P%3DP%28z%3E%5Cfrac%7B42%7D%7B%5Cfrac%7B569%7D%7B%5Csqrt%7B130%7D%7D%7D%29%20%2B%20P%28z%3C-%5Cfrac%7B42%7D%7B%5Cfrac%7B569%7D%7B%5Csqrt%7B130%7D%7D%7D%29)
![P=P(z>0.8416) + P(z](https://tex.z-dn.net/?f=P%3DP%28z%3E0.8416%29%20%2B%20P%28z%3C-0.8416%29)
Looking at the tables for the standard nominal distribution we get
![P =0.1999+0.1999](https://tex.z-dn.net/?f=P%20%3D0.1999%2B0.1999)
![P =0.3998](https://tex.z-dn.net/?f=P%20%3D0.3998)
Exactly the same way you find any missing item in any other subject:
You take the information you're given, and you collect everything you know about
relationships between the information you have and the item you have to find.
Finally, you use the relationships and the given information to find the value of the
missing item.
The process you'll use to find the circumference of a circle will depend on what
information you DO have about the circle.