Answer:
So, the odds that a taxpayer would be audited 28 to 972 or 2.88%
Step-by-step explanation:
Given
Let P(A) = Probability of irs auditing
P(A) = 2.8%
Let n = number of those who earn above 100,000
To get the odds that taxpayer would be audited, we need to first calculated the proportion of those that will be audited and those that won't.
If the probability is 2.8% then 2.8 out of 100 will be audited. That doesn't make a lot of sense since you can't have 2.8 people; we multiply the by 10/10
i.e.
Proportion, P = 2.8/100 * 10/10
P = 28/1000
The proportion of those that would not be audited is calculated as follows;
Q = 1000 - P
By substituton
Q = 1000 - 28
Q = 972
So, the odds that a taxpayer would be audited 28 to 972 or P/Q
P/Q = 28/972
= 0.0288065844
= 2.88% --- Approximately
Answer:
Step-by-step explanation:
Answer:
c) the line should not be solid. the line should be dashed
Recall that, an absolute value expression is a piece-wise in effect, thus we'd check the single-sided limits,
Answer:
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 67
Variance = 3.85
We have to find 80% confidence interval for the population variance of the weights.
Degree of freedom = 67 - 1 = 66
Level of significance = 0.2
Chi square critical value for lower tail =
Chi square critical value for upper tail =
80% confidence interval:
Putting values, we get,
Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.
