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2 years ago

If DF=78, DE=5x-9, and EF=2x+10, find DE.

Mathematics

1 answer:

Kazeer [188]2 years ago

3 0

Given that E is a point between Point D and F, the numerical value of segment DE is 46.

<h3>What is the numerical value of DE?</h3>

Given the data in the question;

E is a point between point D and F.
Segment DF = 78
Segment DE = 5x - 9
Segment EF = 2x + 10
Numerical value of DE = ?

Since E is a point between point D and F.

Segment DF = Segment DE + Segment EF

78 = 5x - 9 + 2x + 10

78 = 7x + 1

7x = 78 - 1

7x = 77

x = 77/7

x = 11

Hence,

Segment DE = 5x - 9

Segment DE = 5(11) - 9

Segment DE = 55 - 9

Segment DE = 46

Given that E is a point between Point D and F, the numerical value of segment DE is 46.

Learn more about equations here: brainly.com/question/14686792

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