Answer: 644,800
Step-by-step explanation:
This can also be solved using the terms of Arithmetic Progressions.
Let the 13 years be number of terms of the sequences (n)
Therefore ;
T₁₃ = a + ( n - 1 )d , where a = 310,000 and d = 9% of 310,000
9% of 310,000 = 9/100 x 310,000
= 27,900
so the common difference (d)
d = 27,900
Now substitute for the values in the formula above and calculate
T₁₃ = 310,000 + ( 13 - 1 ) x 27,900
= 310,000 + 12 x 27,900
= 310,000 + 334,800
= 644,800.
The population after 13 years = 644,800.
Let's solve ~
It's factorized now ~ And if you want to find the zeros then equate the expression with 0.
And you will get ;
