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2 years ago

How do you solve f(x) = x2 + x - 20?

Mathematics

1 answer:

Darina [25.2K]2 years ago

4 0

$\huge \bf༆ Answer ༄$

Let's solve ~

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \: {x}^{2} + x - 20$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \: {x}^{2} + 5x - 4x - 20$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:x(x + 5) - 4(x + 5)$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:(x + 5)(x - 4)$

It's factorized now ~ And if you want to find the zeros then equate the expression with 0.

And you will get ;

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:x = - 5 \: \: and \: \: 4$

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How do you solve f(x) = x2 + x - 20?​

How do you solve f(x) = x2 + x - 20?