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Sonja [21]
2 years ago
13

Solve for p.

Mathematics
1 answer:
jeyben [28]2 years ago
8 0

Answer: C

Step-by-step explanation:

thank me later

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Y=-1/3x^2-4x-5 in vertex form
grigory [225]

Answer:

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

Step-by-step explanation:

Given function:

Y=-\frac{1}{3}x^2-4x-5

We need to find the vertex form which is.,

y=a(x-h)^2+k

where (h,k) represents the co-ordinates of vertex.

We apply completing square method to do so.

We have  

Y=-\frac{1}{3}x^2-4x-5

First of all we make sure that the leading co-efficient is =1.

In order to make the leading co-efficient is =1, we multiply each term with -3.

-3\times Y=-3\times\frac{1}{3}x^2-(-3)\times4x-(-3)\times 5

-3Y=x^2+12x+15

Isolating x^2 and x terms on one side.

Subtracting both sides by 15.

-3Y-15=x^2+12x-15-15

-3Y-15=x^2+12x

In order to make the right side a perfect square trinomial, we will take half of the co-efficient of x term, square it and add it both sides side.  

square of half of the co-efficient of x term = (\frac{1}{2}\times 12)^2=(6)^2=36

Adding 36 to both sides.

-3Y-15+36=x^2+12x+36

-3Y+21=x^2+12x+36

Since x^2+12x+36 is a perfect square of (x+6), so, we can write as:

-3Y+21=(x+6)^2

Subtracting 21 to both sides:

-3Y+21-21=(x+6)^2-21

-3Y=(x+6)^2-21

Dividing both sides by -3.

\frac{-3Y}{-3}=\frac{(x+6)^2}{-3}-\frac{21}{-3}

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

8 0
3 years ago
The function p(x) is an odd degree polynomial with a negative leading coefficient.
Aliun [14]
A because it’s the right answer
4 0
3 years ago
Increase £60 by 120%
zimovet [89]
60×120=7200
7200÷100=72
60+72=132

answer=£132
hope this helps.....
3 0
3 years ago
What is the answer to this question because i do not know 5/12 x =1
Otrada [13]

Answer:

x=12/5

Step-by-step explanation:

x*5/12=1

x=1*12/5

x=12/5

3 0
2 years ago
Read 2 more answers
www.g The physical plant at the main campus of a large state university recieves daily requests to replace fluorescent lightbulb
damaskus [11]

Answer:

z=\frac{24-40}{8}=-2

z=\frac{40-40}{8}=0

And then the percentage between 24 and 40 would be \frac{95}{2}= 47.5 \%

Step-by-step explanation:

For this problem we have the following parameters given:

\mu = 40, \sigma =8

And for this case we want to find the percentage of lightbulb replacement requests numbering between 24 and 40.

From the empirical rule we know that we have 68% of the values within one deviation from the mean, 95% of the values within 2 deviations and 99.7% within 3 deviations.

We can find the number of deviations from themean for the limits with the z score formula we got:

z=\frac{X-\mu}{\sigma}

And replacing we got:

z=\frac{24-40}{8}=-2

z=\frac{40-40}{8}=0

And then the percentage between 24 and 40 would be \frac{95}{2}= 47.5 \%

5 0
3 years ago
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