1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
GuDViN [60]
3 years ago
6

Find the area from the this problem plz

Mathematics
2 answers:
Nuetrik [128]3 years ago
6 0
Area=370
Explantion:
find the area of the big rectangle first(15x30)
Find the area of the smaller rectangle (8x10)
Then subtract the big rectangle from the smaller(450-80=370) then u get ur answer
a_sh-v [17]3 years ago
4 0

Answer:

1

Step-by-step explanation:////

You might be interested in
What is the volume of a cone that has a radius of 4 cm and a height of 9 cm?
vodka [1.7K]
For any sort of pyramid or cone, the volume is 1/3 of the volume of a prism with the same base and height. Since the volume of a prism/cylinder is V=Bh, the volume of a pyramid/cone is V=\frac{1}3Bh.

In this case, our base is a circle, which has a radius of 4 cm.
The area of a circle is A=\pi r^2 where r is the radius.
A=\pi (4)^2=\pi (4\times4)=16\pi=B

We now know that our base is 16π cm.
We also know that our height is 9 cm.
Let's plug these into our volume formula.

V=\frac{1}3\times16\pi \times9

Use 3.14 to approximate pi as the question states. 16 × 3.14 = 50.24.

V\approx\frac{1}3\times50.24\times9

We could punch all of that into our calculator to get the same answer, but since 1/3 of 9 is clearly 3, let's just go with that.

V\approx3\times50.24

\boxed{V\approx150.72\ cm^3}
8 0
3 years ago
Read 2 more answers
Help Plez 20 Points Due Today
Jobisdone [24]

Answer:6.25

Step-by-step explanation :  ratio of areas = one half :two point five in a half        

=1.0:6.25

8 0
3 years ago
Read 2 more answers
Show work / explain it ​
aivan3 [116]
Answer:
X 1 = -4,X 2 =12

EXPLANATION:

Determine the defined range
X+6/x=6/x-8,x#0,x#8

Simplify the equation using cross-multiplication
(X+6) x (x-8)=6x

Move variable to the left-hand side and change its sign
(X-6)x(x-8)-6x=0

Multiply the parentheses
X^2-8x+6x-48-6x=0

Since two opposites add up to zero, remove them from the expression
X^2-8x-48=0

Write -8x as a difference
X^2+4x-12x-48=0

Factor out x from the expression
Xx(x+4)-12x-48=0

Factor out -12 from the expression
Xx(x+4)-12(x+4)=0

Factor out from the expression
(x+4)x(x-12)=0

When the product of factors equals 0, at least one factor is 0
x+4=0
x-12=0

Solve the equation for x
X=-4
X-12=0
X=-4,x#0,x#8

Check if the solution is in the defined range
X=-4
x=12

The equation has 2 solutions

X 1 = -4,X 2 =12

Hope this helps


3 0
3 years ago
MAKE SURE YOU ARE RIGHT ANSWER PLEASE I WILL PUT THE BRAINIEST ANSWER
Pavlova-9 [17]

Step-by-step explanation:

Formula:- 4/3*Pi*r^3

= 4/3*22/7*(1/2)^3

Please mark me as brainliest

8 0
3 years ago
I need help please.....
fgiga [73]

Answer:

C

Step-by-step explanation:

Move the decimal to the right 4 times

7 0
3 years ago
Other questions:
  • I need help with this question? Please and thank you!!!!<br> #15
    8·2 answers
  • Solve for the roots in the following equation. Hint: Factor both quadratic expressions.
    7·2 answers
  • In constructing a box-and-whisker plot for the data set below, at which values would you draw the left and right sides of the bo
    11·1 answer
  • I need to know 7 8 9 10 11
    14·1 answer
  • Find the difference (4ab-9a-8)-(7ab-1)
    6·1 answer
  • Select the mixed number or fraction that is equivalent to 32.029.
    12·1 answer
  • Hillary, Meredith, and Aly are sitting in their favorite coffee shop when their waiter asks: "Does everyone want coffee?" Hillar
    8·1 answer
  • What is the sum of the 12th square number and the 10th square number?
    15·1 answer
  • HELPPPPPPPPPPP!! SMART People?
    15·2 answers
  • What is the average rate of change for the table and graph below over the interval [0,3]?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!