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EleoNora [17]
3 years ago
12

Find the squares of (x+3)​

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
5 0

Answer:

{x}^{2}  + 6x + 9 \\

Step-by-step explanation:

{(x + 3)}^{2}  \\ (x + 3)(x + 3) \\ x(x + 3) + 3(x + 3) \\  {x}^{2}  + 3x + 3x + 9 \\  {x}^{2}  + 6x + 9 \\

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For the level 3 course, exam hours cost twice as much as workshop hours, workshop hours cost twice as much as lecture hours. How
natulia [17]
<h2>Answer</h2>

Cost of lectures = $7.33 per hour

<h2>Explanation</h2>

Let e the cost of the exam hours

Let w be the cost of the workshop hours

Let l be the cost of the lecture hours.

We know from our problem that exam hours cost twice as much as workshop, so:

e=2w equation (1)

We also know that workshop hours cost twice as much as lecture hours, so:

w=2l equation (2)

Finally, we also know that 3hr exams 24hr workshops  and 12hr lectures cost $528, so:

3e+24w+12l=528 equation (1)

Now, lets find the value of l:

Step 1.  Solve for l in equation (3)

3e+24w+12l=528

12l=528-3e-24w equation (4)

Step 2. Replace equation (1) in equation (4) and simplify

12l=528-3e-24w

12l=528-3(2w)-24w

12l=528-6w-24w

12l=528-30w equation (5)

Step 3. Replace equation (2) in equation (5) and solve for l

12l=528-30w

12l=528-30(2l)

12l=528-60l

72l=528

l=\frac{528}{72}

l=\frac{22}{3}

l=7.33

Cost of lectures  = $7.33 per hour



3 0
3 years ago
Read 2 more answers
A man is standing at a radar base and observes an unidentified plane at an altitude 6000m flying towards the radar base at an an
liubo4ka [24]

Answer:

The speed in of the plane is 115.47 m/sec

Step-by-step explanation:

Given:

Height at which the plane is flying = 6000 m

Angle of elevation at the radar base = 30 Degrees

Angle of elevation at the radar base after one minute  = 60 Degrees

To Find:

The Speed of the plane in meter per second = ?

Solution:

Let us use the tangent of the angle to find the distance (d) to a point directly below plane:

<u>when the angle is 30 degrees</u>

tan(30) = \frac{6000}{d1}

d1   = \frac{6000}{tan(30)}

d1 = \frac{6000}{0.577}

d1 = 10392.3 meters

<u>when the angle is 60 degrees</u>

tan(60) = \frac{6000}{d2}

d2  = \frac{6000}{tan(60)}

d2  = \frac{6000}{1.732}\\

d2 = 3464.1 meters

<u>distance travelled by aircraft in 1 min is  </u>

=>d1 - d2

=>0392.3 - 3464.1

= 6928.2 m/min

<u>Now converting to m/sec</u>

=>\frac{6928.2}{60}

=>115.47 m/sec

4 0
3 years ago
Help plz no wrong answers plz help me ASAP thanks!
wariber [46]

Answer:

480

Step-by-step explanation:

The probability she will roll 2 odd numbers is 12/50  (the number of odd rolls over the total).  This simplifies to 6/25

Multiply the probability times the total number of rolls to get a good estimate of the number of rolls that till be odd odd

6/25 * 2000 =480

5 0
3 years ago
Write an inequality for the graph below.<br> 'न<br> 34<br> 10<br> ।। 12 13 14
Rzqust [24]

Answer:

i like cheese wbu hahahahahaha

5 0
3 years ago
THE ANSWER IS 6!!!!!!!!!!!!!!!!!!!!!!
lorasvet [3.4K]

Answer:

6!!!!!!!!!!!!!!!!!!!!!!!

Step-by-step explanation:

5 0
3 years ago
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