4 binary digits have 2^4 = 16 combinations.
The combinations with exactly one 1 are: 1000, 0100, 0010 and 0001. So 4 out of 16 codes have exactly one 1.
The chances of that are 4/16 = 1/4.
12a+b=4962
20a+b=4754
8a=-208
a=-26
-312+b=4962
b=4962+312
b=5274
y=-26x+5274
x=0 -- y=5274
<span>y=0 -- 26x=5274, x=80.85 (approx.)</span>
Answer:
15
Step-by-step explanation:
3/8 = 9
9÷3= 3
the remainder of 3/8 is 5/8 so
5x3=15
Answer:
C
Step-by-step explanation:
i did this in 6th grade too man i gotchu