A pool is being drained at a constant rate. The amount of water is a function of the number of minutes the pool has been drainin g, as shown in the table. Write an equation in slope-intercept form that represents the function. Then find the water in the pool after two and a half hours. Time (mi) 12--------20------50 Volumne (gal) 4962--4754--3974
2 answers:
12a+b=4962 20a+b=4754 8a=-208 a=-26 -312+b=4962 b=4962+312 b=5274 y=-26x+5274 x=0 -- y=5274 <span>y=0 -- 26x=5274, x=80.85 (approx.)</span>
Answer:
Using the first two values in the table, we can first find the slope to write an equation of a line, so we have
[4754 - 4962 ] / [20 - 12 ] = -26
So we have
y - 4754 = -26(x - 20)
y - 4754 = -26x + 520
y = -26x + 5274
Let's confirm that the amount after 50 minutes is correct
y = -26(50) + 5274 = 3974
So after 2 + 1/2 hrs (150 min) we have
y = -26(150) + 5274 = 1374 gallons
Step-by-step explanation:
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