Question

a watermelon is thrown down from the 7th floor of urey hall at ucsd. if the initial height of the watermelon is 21.0 meters, and it is thrown straight downward with an initial downward velocity of 3.00 m/s. how far will the watermelon have fallen from its starting height after 1.50 seconds?

Answer 1

Answer:

The watermelon has fallen 15.53625m

Step-by-step explanation:

x=vi*t+.5*a*t^2

x=3*1.5+.5*9.81*1.5^2

x=15.53625m

Answer 2

The answer would be 15.5