Answer:
Step-by-step explanation:
First put the lower limit, i.e., x=0,
F(x)=8cos[2(0)]=8cos(0)=8(1)=8
;cos(0)=1
Now,put the upper limit of given interval, i.e., x = π,
F(x)=8cos[2(π)]=8cos(2π)=8(1)=8
;cos(2π)=1
Basically you are trying to find two numbers that when they are added equals -2 and when multiplied equals -3. As you can see -3 plus +1 is equal to -2. And 1 times -3 equals -3. Therefore you have (x+1)(x-3). In order to check if these are the right numbers you will need to multiply (x+1)(x-3) and will end up with the first equation x^2-2x-3. Hope this helped! :)
Answer:
They are a Pythagorean triple that forms a right triangle
Step-by-step explanation:
a2 + b2 = c2
(5)^2 + (12)^2 = (13)^2
25 + 144 = 169
(13)^2 = 169
11x+3y=103 and y=3x+1.
11x+3(3x+1)=103 -----> plug in (3x+1) for y in the first equation. You will want to distribute the 3 to the 3x+1 to get something that looks like:
11x+9x+3=103 ------> now you want to combine like terms
20x+3=103 ---> subtract 3 from both sides
20x=100 ----> divide both sides by 20
x=5
y=3(5)+1 ---> I like to plug in this to the equation that already has y isolated. 3*5 is 15, add 1 and you find that y=16.
(5, 16) will be your final answer (:
