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ankoles [38]
3 years ago
15

Find x and y (Please answerrr) ​

Mathematics
1 answer:
m_a_m_a [10]3 years ago
6 0

Answer: idont even know

Step-by-step explanation:

rfcgggggggggggggggggggdrthyjcgfdtey

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Please what is the interquartile range ?
AleksAgata [21]

Answer:

3.

Step-by-step explanation:

15 - 12 = 3.

The ends of the box are the lower and upper quartiles.

The difference  upper - lower = the interquartile range.

6 0
3 years ago
A trade magazine routinely checks the​ drive-through service times of​ fast-food restaurants. An 80​% confidence interval that r
Aleksandr [31]

Answer:

This means that we are 80% confident that the mean of the drive-through service time is between 178.0 seconds and 181.0 seconds. This conclusion was obtained after examined 576 customers. If you want a greater % of confidence you will have to lower the lower bound and increase the upper bound

5 0
3 years ago
Read 2 more answers
Natalia is making a model of a statue using a scale in which 7 centimeter equals 4 feet. If the model is 3.5 centimeters wide, w
Serhud [2]

Answer:

2 ft

Step-by-step explanation:

\dfrac{7}{4} = \dfrac{3.5}{x}

7x = 4 \times 3.5

x = 2

Answer: 2 ft

7 0
3 years ago
6
8090 [49]

Answer:

James bought 11 good tickets and 5 bad tickets.

Step-by-step explanation:

Given that:

Cost of each good ticket = $8

Cost of each bad ticket = $5

Total amount spent = $113

Total tickets bought = 16

Let,

x be the number of good tickets bought

y be the number of bad tickets bought

x+y=16     Eqn 1

8x+5y=113    Eqn 2

Multiplying Eqn 1 by 5

5(x+y=16)

5x+5y=80    Eqn 3

Subtracting Eqn 3 from Eqn 2

(8x+5y)-(5x+5y)=113-80

8x+5y-5x-5y=33

3x=33

Dividing both sides by 3

\frac{3x}{3}=\frac{33}{3}\\x=11

Putting x=11 in Eqn 1

11+y=16

y=16-11

y=5

Hence,

James bought 11 good tickets and 5 bad tickets.

3 0
3 years ago
completa con las razones trigonométricas de cada triángulo rectángulo dado y encuentra el lado faltante aplicando el teorema de
Rus_ich [418]

primero vamos a calcular el lado faltante usando el teorema de pitagoras para poder obtener el lado faltante a

a=\sqrt[]{hipotenusa^2-cateto^2}a=\sqrt[]{100^2-85^2}=52.68

a=52.68 m

teniendo el lado faltante podemos calcular las razones trigonometricas

\sin (55)=\frac{85}{100}=0.85\cos (55)=\frac{52.68}{100}=0.52\tan (55)=\frac{85}{52.68}=1.61

\csc (55)=\frac{100}{85}=1.17\sec (55)=\frac{100}{52.68}=1.89\cot (55)=\frac{52.68}{85}=0.61

4 0
1 year ago
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