Answer:
(-1,6)
Explanation:
use (y1-y2), (x1-x2)
The weight of the new student is 27 kg.
Average weight
= total weight ÷total number of students
<h3>
1) Define variables</h3>
Let the total weight of the 35 students be y kg and the weight of the new student be x kg.
<h3>2) Find the total weight of the 35 students</h3>
<u>
</u>
y= 35(45)
y= 1575 kg
<h3>3) Write an expression for average weight of students after the addition of the new student</h3>
New total number of students
= 35 +1
= 36
Total weight
= total weight of 35 students +weight of new students
= y +x

<h3>4) Substitute the value of y</h3>

<h3>5) Solve for x</h3>
36(44.5)= 1575 +x
1602= x +1575
<em>Subtract 1575 from both sides:</em>
x= 1602 -1575
x= 27
Thus, the weight of the new student is 27 kg.
Answer:
Intercepts:
x = 0, y = 0
x = 1.77, y = 0
x = 2.51, y = 0
Critical points:
x = 1.25, y = 4
x = 2.17
, y = -4
x = 2.8, y = 4
Inflection points:
x = 0.81, y = 2.44
x = 1.81, y = -0.54
x = 2.52, y = 0.27
Step-by-step explanation:
We can find the intercept by setting f(x) = 0


where n = 0, 1, 2,3, 4, 5,...

Since we are restricting x between 0 and 3 we can stop at n = 2
So the function f(x) intercepts at y = 0 and x:
x = 0
x = 1.77
x = 2.51
The critical points occur at the first derivative = 0


or

where n = 0, 1, 2, 3

Since we are restricting x between 0 and 3 we can stop at n = 2
So our critical points are at
x = 1.25, 
x = 2.17
, 
x = 2.8, 
For the inflection point, we can take the 2nd derivative and set it to 0



We can solve this numerically to get the inflection points are at
x = 0.81, 
x = 1.81, 
x = 2.52, 
Given the expression below

To find n
Open the brackets

Collect like terms

Since, the sides are not equal,
Hence, there is no solution