Answer:
c
Step-by-step explanation:
150 is a good sample of a middle school and students at lunch is random again because most students eat lunch
Answer:
And rounded up we have that n=385
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
Solution to the problem
In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by
and
. And the critical value would be given by:
The margin of error for the proportion interval is given by this formula:
(a)
And on this case we have that
and we are interested in order to find the value of n, if we solve n from equation (a) we got:
(b)
We can use as an estimator for p
. And replacing into equation (b) the values from part a we got:
And rounded up we have that n=385
Work shown above! Answer would be 110 degrees!
→4(2) which can be referred to as 4 + 4
→14 (4)<span>= 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 </span> which also equal to → 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 +4 + 4 +4 +4 + 4 +4 +4
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