Complete question :
Standardized tests: In a particular year, the mean score on the ACT test was 19.3 and the standard deviation was 5.3. The mean score on the SAT mathematics test was 532 and the standard deviation was 128. The distributions of both scores were approximately bell-shaped. Round the answers to at least two decimal places. Part: 0/4 Part 1 of 4 (a) Find the z-score for an ACT score of 26. The Z-score for an ACT score of 26 is
Answer:
1.26
Step-by-step explanation:
Given that:
For ACT:
Mean score, m = 19.3
Standard deviation, s = 5.3
Zscore for ACT score of 26;
Using the Zscore formula :
(x - mean) / standard deviation
x = 26
Zscore :
(26 - 19.3) / 5.3
= 6.7 / 5.3
= 1.2641509
= 1.26
To solve this problem we must find 5% of 1418 and 4% of 1418
which is

so that would be 70.9 house extra in the first year and 56.72 extra in the second year respectively.
so to find the total number of houses we must add 70.9 + 56.72 + 1418 which gives us 1545.62
at the last it is mentioned for us to round our answer to the nearest
they are asking us for the total number whole number
which is 1546
so there would be 1546 houses in the second year.
To find the next number in the sequence, multiply the number before by 2.
By this logic, numbers 4-8 in the sequence would be 152, 304, 608, 1,216, and 2,432
Thus, the 8th term is 2,432
Answer:
x = ± sqrt(43)
Step-by-step explanation:
2x^2 - 28 = x^2 + 15
Subtract x^2 from each side
2x^2-x^2 - 28 = x^2-x^2 + 15
x^2 -28 = 15
Add 28 to each side
x^2 - 28 +28= 15+28
x^2 = 43
Take the square root of each side
sqrt(x^2) = ± sqrt(43)
x = ± sqrt(43)