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aivan3 [116]
3 years ago
7

The ratio of an object's weight on Earth to its weight on Neptune is 5:7. How much would a person who weighs 150 pounds on Earth

weigh on Neptune? A. 170 pounds B. 1071⁄7 pounds C. 210 pounds D. 750 pounds
Mathematics
2 answers:
navik [9.2K]3 years ago
8 0

Answer: Option C

Step-by-step explanation:

We know that the the ratio is 5:7

this means that if the object in the Earth weights 7kg, in neptune it will weight 5 kg in Neptune

This means that the weight in Earth is related to the weight in Neptune by:

We = 5/7Wn

then, if a person weights 150 punds in Earth, we have that:

We = 150 pounds = 5/7*Wn

Wn = 7/5*150pounds = 210 pounds

the correct option is option C

jarptica [38.1K]3 years ago
4 0

5/7 = 150 / ?

using cross product

5 * ? = 7 * 150

? = 7 * 150 / 5

210 lbs

Choice C

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sqrt(360)

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Profit, P(x), is the difference between revenue, R(x), and cost, C(x), so P(x) = R(x) - CC). Which
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Answer:

Step-by-step explanation:

Profit, P(x), is the difference between revenue, R(x), and cost, C(x)

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Substituting into the equation

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7 0
3 years ago
Read 2 more answers
Sara has $50 in her wallet in $5 and $20 bills. Create a linear equation (with
77julia77 [94]

Answer:

<em>0 $20 bills and 10 $5 bills</em>

<em>1 $20 bills and 6 $5 bills</em>

<em>2 $20 bills and 2 $5 bills</em>

Step-by-step explanation:

<u>Equations</u>

Let's set:

x=number of $5 bills

y=number of $20 bills

The total amount Sara has is given by

5x+20y

And we know it's equal to $50, thus:

5x+20y=50

Dividing by 5

x+4y=10

We would need another condition to solve for x and y, but we can determine some combinations that solve the problem.

Solving for x:

x=10-4y

Since both x and y are integers and cannot be negative:

10-4y≥0

Swapping sides:

4y≤10

Dividing by 4:

y≤2.5

Thus, y can only have the values {0,1,2}

For y=0

x=10-4*0=10

x=10

For y=1

x=10-4*1=6

x=6

For y=2

x=10-4*2=2

x=2

Thus, the possible combinations are:

0 $20 bills and 10 $5 bills

1 $20 bills and 6 $5 bills

2 $20 bills and 2 $5 bills

4 0
3 years ago
Write one digit on each side of 23 to make a four digit multiple of 72. How many different solutions does this problem have?
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Answer:

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Step-by-step explanation:

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To be divisible by both 8 and 9 at the same time.

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Between 12 and 20, only 18 is divisible by 9. So we need a = 7

5 0
3 years ago
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