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aivan3 [116]
3 years ago
7

The ratio of an object's weight on Earth to its weight on Neptune is 5:7. How much would a person who weighs 150 pounds on Earth

weigh on Neptune? A. 170 pounds B. 1071⁄7 pounds C. 210 pounds D. 750 pounds
Mathematics
2 answers:
navik [9.2K]3 years ago
8 0

Answer: Option C

Step-by-step explanation:

We know that the the ratio is 5:7

this means that if the object in the Earth weights 7kg, in neptune it will weight 5 kg in Neptune

This means that the weight in Earth is related to the weight in Neptune by:

We = 5/7Wn

then, if a person weights 150 punds in Earth, we have that:

We = 150 pounds = 5/7*Wn

Wn = 7/5*150pounds = 210 pounds

the correct option is option C

jarptica [38.1K]3 years ago
4 0

5/7 = 150 / ?

using cross product

5 * ? = 7 * 150

? = 7 * 150 / 5

210 lbs

Choice C

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he following data represent the times in minutes required for 18 co-workers to commute to work. 48 42 31 29 41 22 38 38 21 39 22
labwork [276]

Answer:

1, 2, 2, 2, 3, 8, 9

Step-by-step explanation:

The following data represent the times in minutes required for 18 co-workers to commute to work

48 42 31 29 41 22 38 38 21 39 22 48 22 12 34 32 23 28

Rewrite this data in ascending order

12 21 22 22 22 23 28 29 31 32 34 38 38 39 41 42 48 48    

Now, the stem-and-leaf plot is

\begin{array}{cc}\text{Stem}&\text{Leaf}\\ \\1&2\\2&1,2,2,2,3,8,9\\3&1,2,4,8,8,9\\4&1,2,8,8\end{array}

The second row represents the leaves for the given data points in the range 20 to 29 for this stem-and-leaf plot, so the answer is

1, 2, 2, 2, 3, 8, 9

3 0
3 years ago
PLEASE SHOW WORK
CaHeK987 [17]

(C)

Step-by-step explanation:

The volume of the conical pile is given by

V = \dfrac{\pi}{3}r^2h

Taking the derivative of V with respect to time, we get

\dfrac{dV}{dt} = \dfrac{\pi}{3}\dfrac{d}{dt}(r^2h)

\:\:\:\:\:\:\:= \dfrac{\pi}{3}\left(2rh\dfrac{dr}{dt} + r^2\dfrac{dh}{dt}\right)

Since r is always equal to h, we can set

\dfrac{dr}{dt} = \dfrac{dh}{dt}

so that our expression for dV/dt becomes

\dfrac{dV}{dt} = \dfrac{\pi}{3}\left(3r^2\dfrac{dh}{dt}\right)

\:\:\:\:\:\:\:= \pi r^2\dfrac{dh}{dt}

Solving for dh/dt, we get

\dfrac{dh}{dt} = \dfrac{1}{\pi r^2}\dfrac{dV}{dt}

\:\:\:\:\:\:\:= \dfrac{1}{9\pi\:\text{m}^2}(36\:\text{m}^3\text{/s})

\:\:\:\:\:\:\:= \dfrac{4}{\pi}\:\text{m/s}

7 0
3 years ago
Bridget went fishing with her dad. Bridget Bridget caught the first fish of the day, another was 2 more than 3 times the weight
Arturiano [62]

Answer:

Bridget's first fish =f = 5 ounces

Bridget's dad first fish weighs 17 ounces

Step-by-step explanation:

Solution:

Bridget's fishes:

f ounces

2f ounces

3f+2 ounces

1/2f ounces

3/5f ounces

Total= f +2f + (3f+2) + 1/2f +3/5f

=3f + 3f + 2 + 5f+6f/10

=6f + 2 + 11f/10

=60f+11f/10 +2

=71/10f +2

Bridget's dad fishes

3f+2

4/5f

2f+4

1/2f

Total =(3f+2) + (2f+4) + 4/5f +1/2f

=3f+2+2f+4 + 8f+5f/10

=5f + 6 + 13/10f

= 50f+13f/10 + 6

=63/10f +6

Equate the total weight

71/10f +2=63/10f +6

Collect like terms

71/10f - 63/10f =6-2

71f-63f/10 = 4

8f/10=4

Cross product

8f=40

Divide both sides by 8

f=5

Bridget's first fish =f = 5 ounces

Bridget's dad first fish = 3f +2

=3(5)+2

=15+2

=17 ounces

Bridget's dad first fish weighs 17 ounces

8 0
3 years ago
How would i solve for x and y in 3x+2y=17 and 2x-y=2 by using substitution
maxonik [38]
I’ll do an example problem, and I challenge you to do this on your own!
4x+6y=23
7y-8x=5
Solving for y in 4x+6y=23, we can separate the y by subtracting both sides by 4x (addition property of equality), resulting in 6y=23-4x. To make the y separate from everything else, we divide by 6, resulting in (23-4x)/6=y. To solve for x, we can do something similar - subtract 6y from both sides to get 23-6y=4x. Next, divide both sides by 4 to get (23-6y)/4=x.

Since we know that (23-4x)/6=y, we can plug that into 7y-8x=5, resulting in
7*(23-4x)/6-8x=5
= (161-28x)/6-8x
Multiplying both sides by 6, we get 161-28x-48x=30
= 161-76x
Subtracting 161 from both sides, we get -131=-76x. Next, we can divide both sides by -76 to separate the x and get x=131/76. Plugging that into 4x+6y=23, we get 4(131/76)+6y=23. Subtracting 4(131/76) from both sides, we get
6y=23-524/76. Lastly, we can divide both sides by 6 to get y=(23-524/76)/6

Good luck, and feel free to ask any questions!
4 0
3 years ago
Ty’s experimental probability of winning a certain game is 1/3. Jana’s expiremental probability of winning the same game is 3/4.
Dafna1 [17]

Answer:

Jana is expected to win 40 more games over Ty.

Step-by-step explanation:

If Ty plays the game 120 times, he is expected to win in 1/3 part of 120 games, which is ( 1/3 * 120 =) 40 games.

If Jana plays the game 120 times, she is expected to win in 2/3 part of 120 games, which is ( 2/3 * 120 =) 80 games.

If Jana is expected to win 80 times an Ty is expected to 40 times, then Jana is expected to win ( 80 - 40 =) 40 more games over Ty.

4 0
3 years ago
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