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2 years ago

PLEASE HELPPPPPP EASY

Mathematics

1 answer:

lianna [129]2 years ago

5 0

The answer to your question is D

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The melting point of substance X is -20 degrees Celsius and the boiling point is 90 degrees Celsius. How many Celsius degrees ar

Kazeer [188]

To find the distance between 2 numbers you must take the absolute value of the difference

|90-(-20)|
|110|
110

110 degrees celsius

3 0

2 years ago

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If x^2 = 16(5), then x =

Bogdan [553]

Answer:

$4\sqrt{5}$ or 8.944

Step-by-step explanation:

$x^{2} = 16(5)$

Simplify

$x^{2} =80$

Square root both sides to get x by itself

$\sqrt{x^{2} } =\sqrt{80}$

$4\sqrt{5}$ or 8.944

6 0

3 years ago

Solve 3(4m - 6) = 12 and explain each step

Studentka2010 [4]

Distribute the 3 to 4m and 6. this makes 12m-18=12
now add 18 to both sides.
12m=30
now divide by 12
m=30/12

3 0

3 years ago

Solve for x please I need help

ser-zykov [4K]

Answer: picture wont seem to load, maybe try again

Step-by-step explanation:

8 0

2 years ago

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The total cost (in hundreds of dollars) to produce x units of a product is c(x) = (3x-2) / (8x+1), find the average cost for eac

olya-2409 [2.1K]

Answer:

a) $\frac{74}{10025}$

b) $\frac{3x-2}{x(8x+1)}$

c) $\frac{-24x^2+32x-2}{(8x^2+x)^2}$

Step-by-step explanation:

For total cost function $c(x)$ , average cost is given by $\frac{c(x)}{x}$ i.e., total cost divided by number of units produced.

Marginal average cost function refers to derivative of the average cost function i.e., $\left ( \frac{c(x)}{x} \right )'$

Given: $c(x)=\frac{3x-2}{8x+1}$

Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

At x = 50 units,

$\frac{c(50)}{50}=\frac{150-2}{50(400+1)}=\frac{148}{50(401)}=\frac{74}{10025}$

Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

Marginal average cost:

Differentiate average cost with respect to $x$

Take $f=3x-2\,,\,g=8x^2+x$

using quotient rule, $\left ( \frac{f}{g} \right )'=\frac{f'g-fg'}{g^2}$

Therefore,

$\left ( \frac{c(x)}{x} \right )'=\left ( \frac{3x-2}{8x^2+x} \right )'\\=\left ( \frac{3(8x^2+x)-(16x+1)(3x-2)}{(8x^2+x)^2} \right )\\=\frac{24x^2+3x-48x^2-3x+32x+2}{(8x^2+x)^2}\\=\frac{-24x^2+32x-2}{(8x^2+x)^2}$

3 0

3 years ago