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Schach [20]
3 years ago
13

PLEASE HELPPPPPP EASY

Mathematics
1 answer:
lianna [129]3 years ago
5 0
The answer to your question is D
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Which equation has a constant of proportionality of 4? y = x + 4 y = x - 4 y = 4x y = 1/4x
Assoli18 [71]
Y=1/4x im pretty sure
5 0
3 years ago
Suppose that A is nonsingular. Prove that its inverse A-1 is unique. [Hint: Show that if there exists two matrices, B and C, suc
Bogdan [553]

Answer with Step-by-step explanation:

Let A is non-singular

\mid A\mid\neq 0

We have to prove that A^{-1} is unique.

Suppose B and C are inverse of A such that

BA=I and AC=I

By using property AA^{-1}=A^{-1}A=I

C=C

(BA)C=B(AC)

I\cdot C=B\cdot I

C=B

Hence, the inverse of A is unique.

4 0
3 years ago
Find and correct the error of the following factor.
pshichka [43]

3x² + xy2 – 3xy-y? >> 3x² - xy - y

line 1: = (3x² + xy2)+(-3xy – y?)

ANS 3x² - xy - y 《Correct》

line 2: = x(3x + y2) - y(3x – y2)

ANS 3x² - xy +2y²

line 3: = (x-y) (3x +y?)

ANS 3x² - 2xy - y²

If it incorrect, I'm sorry.

3 0
4 years ago
A local charity sponsors a 5K race to raise money. It receives $25 per race entry and $5,000 in donations, but it must spend $5
Katena32 [7]
<span>The charity needs at least 1001 entries to raise more than $25000. Let n be the number of race entries, i be the income of the race, and c the cost of the race. The money that the 5K brings in is given by i = 25 * n + 5000 The cost is given by c = n * 5 Now if the charity needs to raise more than 25000 then the income minus the cost must be greater than 25000. 25000 < i - c subsituting for i and c 25000 < i - c = (25 * n + 5000 ) - (5 * n) simplifying results in 25000 < 25*n - 5*n + 5000 25000 < 20*n + 5000 20000 < 20*n 1000 < n The number of entries must be greater than 1000. Since entries must be an integer the charity needs at least 1001 entries.</span>
5 0
3 years ago
What is the expanded form of 340,729​
babymother [125]

Answer:

(300,000 + 20,000 + 0 + 700 + 40 + 9)

Step-by-step explanation:

The expanded form of 320, 749

Segmenting each digit in the figure based on its place value :

3 = 100 thousand place = 3 * 100,000 = 300000

2 = ten thousand place = 2 * 10,000 = 20000

0 = thousand place = 0 * 1,000 = 0

7 = hundred place = 7 * 100 = 700

4 = tens place = 4 * 10 = 40

9 = unit place = 9 = 9

(300,000 + 20,000 + 0 + 700 + 40 + 9)

3 0
3 years ago
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