Answer: The hook would be 2.2 inches (approximately) above the top of the frame
Step-by-step explanation: Please refer to the picture attached for further details.
The top of the picture frame has been given as 9 inches and a 10 inch ribbon has been attached in order to hang it on a wall. The ribbon at the point of being hung up would be divided into 5 inches on either side (as shown in the picture). The line from the tip/hook down to the frame would divide the length of the frame into two equal lengths, that is 4.5 inches on either side of the hook. This would effectively give us two similar right angled triangles with sides 5 inches, 4.5 inches and a third side yet unknown. That third side is the distance from the hook to the top of the frame. The distance is calculated by using the Pythagoras theorem which states as follows;
AC^2 = AB^2 + BC^2
Where AC is the hypotenuse (longest side) and AB and BC are the other two sides
5^2 = 4.5^2 + BC^2
25 = 20.25 + BC^2
Subtract 20.25 from both sides of the equation
4.75 = BC^2
Add the square root sign to both sides of the equation
2.1794 = BC
Rounded up to the nearest tenth, the distance from the hook to the top of the frame will be 2.2 inches
Answer:
The equation of the line would be y = -5/2x - 1
Step-by-step explanation:
In order to find the equation of the line, we first need to find the slope of the original line. We can do that by solving for y.
5x + 2y = 12
2y = -5x + 12
y = -5/2x + 6
Now that we have a slope of -5/2, we know the new slope will be the same since parallel lines have the same slope. So we can use it along with the point in point-slope form to find the equation.
y - y1 = m(x - x1)
y - 4 = -5/2(x + 2)
y - 4 = -5/2x - 5
y = -5/2x - 1
Since drapes have to be covered all over the window and the beneath of the window, both lengths have to be added.
(2 2/3) + ( 2 3/4)
(8/3) + (11/4)
(32+33)/12
65/12
5 5/12
SA = 2lw + 2lh + 2hw
SA = 2(15)(2) + 2(15)(6) + 2(6)(2)
SA = 60 + 180 + 24
SA = 264
The correct answer is the first choice, ($1818.30, $5077.70.)
To find this, we first find the z-score based on the confidence level:
Convert 95% to a decimal: 95%=95/100 = 0.95
Subtract from 1: 1-0.95 = 0.05
Divide by 2: 0.05/2 = 0.025
Subtract from 1: 1-0.025 = 0.975
Using a z-table (http://www.z-table.com) we see that this value is associated with a z-score of 1.96.
Next, we identify
Next we find
Next we find
Next, we multiply this value by z:
1.96(831.479) = 1629.70
The confidence interval is given by
