Question

Root of 3 (2root2-2root3)

Answer 1

Answer:

$\bf 2 ( \sqrt{6} - 3)$

Step-by-step explanation:

$\sf \sqrt{3} (2 \sqrt{2} - 2 \sqrt{3} )$

$\sf = \sqrt{3} \times 2 \sqrt{2} - 3 \times 2 \sqrt{3}$

$\sf = 2 \sqrt{6} - \sqrt{3} \times 2 \sqrt{3}$

$\sf = 2 \sqrt{6} - 6$

$\sf = 2 ( \sqrt{6} - 3)$

Conclusion:

Simple form of $\sf \sqrt{3} (2 \sqrt{2} - 2 \sqrt{3} )$ is $\bf 2 ( \sqrt{6} - 3)$.

Answer 2

$\\ \sf \longmapsto \: \sqrt{3}(2 \sqrt{2} - 2 \sqrt{3} ) \\ \\ \sf \longmapsto \: 2 \sqrt{6} - 2 \sqrt{9} \\ \\ \sf \longmapsto \: 2 \sqrt{6} - 2(3) \\ \\ \sf \longmapsto \: 2 \sqrt{6} - 6 \\ \\ \sf \longmapsto \: 2( \sqrt{6 } - 3)$