Answer:
39
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Step-by-step explanation:
Since you want to find the variable x all you have to do is simple subtraction.
The two numbers (61 and 22). Subtract those numbers and you get 39. Now it wants you to round to the jearest hundredth but there is no hundreds place so we can round to the nearest tenth. Which would be 30! Hope it helped... :)!
Bye! I did this same answer on this same problem that you posted again.
do you know the way????????????????
Answer:
<h2>A. x + 4</h2>
Step-by-step explanation:
(f - g)(x) = f(x) - g(x)
f(x) = 3x + 2, g(x) = 2x - 2.
Substitute:
(f - g)(x) = (3x + 2) - (2x - 2) = 3x + 2 - 2x - (-2) = 3x + 2 - 2x + 2
<em>combine like terms</em>
(f - g)(x) = (3x - 2x) + (2 + 2) = x + 4
Okay, so Sang is standing 20 yards away from one corner, and Jazmin is standing 99 yards away from the same corner. If this is a rectangle (I like visuals, so I'll use them to explain), then:
99ft
A ------------------------- B
| |
20 ft | |
| |
C -------------------------- D
The question is asking you to solve for the diagonal line between points C and B. If you imagine a line there, you actually have the rectangle split into two triangles. So if you have triangle ABC, side CB would be the longest line, or the hypotenuse. That means you can use the Pythagorean Theorem to solve the problem.
A^2 + B^2 = C^2
99^2 + 20^2 = C^2
9,801 + 400 = C^2
10,201 = C^2
Now you solve for the square root of 10,201 to get C.
sqr (10,201) = C
C = 101 yards
Answer:
4.05 miles.
Step-by-step explanation:
See the attached diagram. (not in scale)
Let AB is the Clayton Road and its length is 2.35 miles and BC is the Wood Pike Road and it is 1.7 miles long.
So, the combined length of Clayton Road and Wood Pike Road is AC (= AB + BC)
So, the length of AC will be (2.35 +1.7) miles = 4.05 miles. (Answer)
