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2 years ago

10

The diameter of a circle is 16 units. What is the radius of the circle?

1 answer:

Licemer1 [7]2 years ago

3 0

Answer:

radius is diameter over two

Step-by-step explanation:

so 16 divided by two will be 8

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What is the solution to the equation? 78=m32

tekilochka [14]

Step-by-step explanation:

78 = m32

m = 78/32 = 39/16 = 2.4375

6 0

2 years ago

Hey I'm really struggling what is 2×3 I've been really struggling, get back when u can thanks

IRINA_888 [86]

Answer:

Hey buddy,

Step-by-step explanation:

2 multiplied by 3 is equal to 6 And 3 groups of 2 is 6. Instead of adding everytime multiplication is much easier .

5 0

3 years ago

Read 2 more answers

So I have this question I don't understand, It says Combine terms

3241004551 [841]

Answer:

14x+13y-15

Step-by-step explanation:

This is pretty simple. When it asks to combine terms, simply add up all of the same terms. So, all the numbers with x, all with y, and all with no value. For example, for x, we simply add up 5x+8x+x, with x equaling 1.

Hope this helps!

8 0

2 years ago

Read 2 more answers

The partial fraction decomposition of 9 x 11 6 x 2 23 x 21 can be written in the form of f ( x ) 2 x 3 g ( x ) 3 x 7 , where

svlad2 [7]

Answer:

$f(x) = -1$

$g(x) =6$

$\frac{-1}{2x + 3} + \frac{6}{3x + 7}$

Step-by-step explanation:

The question is unreadable, however the real polynomial is:

The polynomial fraction is:

$P = \frac{9x + 11}{6x^2 + 23x + 21}$

And the decomposition is:

$\frac{f(x)}{2x + 3} + \frac{g(x)}{3x + 7}$

The solution is as follows:

$P = \frac{f(x)}{2x + 3} + \frac{g(x)}{3x + 7}$

Substitute the expression for P

$\frac{9x + 11}{6x^2 + 23x + 21} = \frac{f(x)}{2x + 3} + \frac{g(x)}{3x + 7}$

Expand the numerator of the polynomial

$\frac{9x + 11}{(2x + 3)(3x + 7)} = \frac{f(x)}{2x + 3} + \frac{g(x)}{3x + 7}$

Take LCM

$\frac{9x + 11}{(2x + 3)(3x + 7)} = \frac{f(x)*(3x + 7) + g(x)*(2x + 3)}{(2x + 3)(x + 7)}$

Cancel out both denominators

$9x + 11} = f(x)*(3x + 7) + g(x)*(2x + 3)$

Represent f(x) as A and g(x) as B

$9x + 11} = A*(3x + 7) + B*(2x + 3)$

Open bracket

$9x + 11} = 3Ax + 7A + 2Bx + 3B$

$9x + 11} = 3Ax + 2Bx+ 7A + 3B$

$9x + 11} = (3A + 2B)x+ 7A + 3B$

By comparison:

$3A + 2B = 9$ ---- (1)

$7A + 3B =11$ ---- (2)

Make B the subject in (1)

$B = \frac{9 - 3A}{2}$

Substitute $B = \frac{9 - 3A}{2}$ in (2)

$7A + 3(\frac{9 - 3A}{2}) = 11$

Multiply through by 2

$2*7A +2* 3(\frac{9 - 3A}{2}) = 11*2$

$14A + 3(9 - 3A) = 22$

$14A + 27 - 9A = 22$

Collect Like Terms

$14A - 9A = 22-27$

$5A = -5$

$A = \frac{-5}{5}$

$A = -1$

Recall that:

$B = \frac{9 - 3A}{2}$

$B = \frac{9 - 3 * -1}{2}$

$B = \frac{9 + 3}{2}$

$B = \frac{12}{2}$

$B = 6$

A = -1 and B = 6

$3A + 2B = 9$ ---- (1)

$7A + 3B =11$ ---- (2)

So:

$f(x) = A$

$f(x) = -1$

$g(x) =B$

$g(x) =6$

And the decomposition is:

$\frac{-1}{2x + 3} + \frac{6}{3x + 7}$

6 0

2 years ago

What is the Nth term of 0 3 8 15 24 35

Rudik [331]

Difference = 3,5,7,9,11...
2nd difference = 2
difference = (2n+1)
gradient = 2n
integral of 2n = n^2.
n^2 = 1,4,9...
n^2 - 1

8 0

2 years ago