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2 years ago

14

The sum of four consecutive integers is between 72 and 91. Find all the groups of integer,

1 answer:

Contact [7]2 years ago

4 0

Answer:

https://www.mathcelebrity.com/sum-of-four-consecutive-numbers.php?num=72-91&pl=Calculate

Step-by-step explanation:

use this website and understand the steps

sorry if i wasn't that big of a help

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In a long-jump competition, Connor jumped 160 centimetres.

xeze [42]

Answer:

290 cm

Step-by-step explanation:

There are 100 centimeters in a meter so 1.3m*100 is 130cm

130+160cm is 290cm.

6 0

2 years ago

Can someone please help me with #37

kolbaska11 [484]

Using the diagram, we can conclude that the radius is 10 feet, and the height is 6 feet.

Plug in the values for radius and height into the equation.
V = π10^2*6
Simplify in terms of pi.
V = 600π
Round pi to 3.14 and multiply by 600.
V = 1,884

1,884 cubic feet is your answer.
In the image you provided, I do not see a fourth option that includes 1,884 cubic feet. I would assume that the camera did not take a full picture of the answer choices.

4 0

3 years ago

Workers inc. just bought 14 boxes of pens to put in their storage room for employees to use as needed. each box contains 50 pens

slega [8]

Answer:

568 pens.

Step-by-step explanation:

Total number of pens bought = 14 * 50 = 700.

Total pens taken by the workers = 33 * 4 = 132.

Number left = 700 - 132 = 568.

4 0

3 years ago

Read 2 more answers

The vertices of ∆ABC are A(-2, 2), B(6, 2), and C(0, 8). The perimeter of ∆ABC is units is? What is the area?

11111nata11111 [884]

we have

$A(-2, 2),B(6, 2),C(0, 8)$

see the attached figure to better understand the problem

we know that

The perimeter of the triangle is equal to

$P=AB+BC+AC$

and

the area of the triangle is equal to

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB\\heigth=DC$

we know that

The distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step $1$

<u>Find the distance AB</u>

$A(-2, 2),B(6, 2)$

Substitute the values in the formula

$d=\sqrt{(2-2)^{2}+(6+2)^{2}}$

$d=\sqrt{(0)^{2}+(8)^{2}}$

$dAB=8\ units$

Step $2$

<u>Find the distance BC</u>

$B(6, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-6)^{2}}$

$d=\sqrt{(6)^{2}+(-6)^{2}}$

$dBC=6\sqrt{2}\ units$

Step $3$

<u>Find the distance AC</u>

$A(-2, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0+2)^{2}}$

$d=\sqrt{(6)^{2}+(2)^{2}}$

$dAC=2\sqrt{10}\ units$

Step $4$

<u>Find the distance DC</u>

$D(0, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-0)^{2}}$

$d=\sqrt{(6)^{2}+(0)^{2}}$

$dDC=6\ units$

Step $5$

<u>Find the perimeter of the triangle</u>

$P=AB+BC+AC$

substitute the values

$P=8\ units+6\sqrt{2}\ units+2\sqrt{10}\ units$

$P=22.81\ units$

therefore

The perimeter of the triangle is equal to $22.81\ units$

Step $6$

<u>Find the area of the triangle</u>

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB=8\ units\\heigth=DC=6\ units$

substitute the values

$A=\frac{1}{2}*8*6$

$A=24\ units^{2}$

therefore

the area of the triangle is $24\ units^{2}$

4 0

3 years ago

Read 2 more answers

Find the first term of the arithmetic sequence in which a38= -5 and the common difference is -2.9

mestny [16]

Answer:

102.3

Step-by-step explanation:

a_38 = -5

difference d= -2.9

We use general formula

$a_n = a_1 + (n-1)d$

WE make the formula for a_38 th term

Plug in 38 for n

$a_{38} = a_1 + (38-1)d$

Now plug in -2.9 for d and -5 for a_38

$-5 = a_1 + (38-1)(-2.9)$

$-5 = a_1 - 107.3$

Now add 107.3 on both sides

102.3 = a_1

option A is correct

3 0

3 years ago

Read 2 more answers