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Korvikt [17]
2 years ago
14

The sum of four consecutive integers is between 72 and 91. Find all the groups of integer,

Mathematics
1 answer:
Contact [7]2 years ago
4 0

Answer:

https://www.mathcelebrity.com/sum-of-four-consecutive-numbers.php?num=72-91&pl=Calculate

Step-by-step explanation:

use this website and understand the steps

sorry if i wasn't that big of a help

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Guys help please I am struggling
alina1380 [7]

9514 1404 393

Answer:

  14.1 years

Step-by-step explanation:

Use the compound interest formula and solve for t. Logarithms are involved.

  A = P(1 +r/n)^(nt)

amount when P is invested for t years at annual rate r compounded n times per year.

Using the given values, we have ...

  13060 = 8800(1 +0.028/365)^(365t)

  13060/8800 = (1 +0.028/365)^(365t) . . . . divide by P=8800

Now we take logarithms to make this a linear equation.

  log(13060/8800) = (365t)log(1 +0.028/365)

Dividing by the coefficient of t gives us ...

  t = log(13060/8800)/(365·log(1 +0.028/365)) ≈ 0.171461/0.0121598

  t ≈ 14.1

It would take about 14.1 years for the value to reach $13,060.

8 0
3 years ago
Use any of the methods to determine whether the series converges or diverges. Give reasons for your answer.
Aleks [24]

Answer:

It means \sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6} also converges.

Step-by-step explanation:

The actual Series is::

\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}

The method we are going to use is comparison method:

According to comparison method, we have:

\sum_{n=1}^{inf}a_n\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n

If series one converges, the second converges and if second diverges series, one diverges

Now Simplify the given series:

Taking"n^2"common from numerator and "n^6"from denominator.

=\frac{n^2[7-\frac{4}{n}+\frac{3}{n^2}]}{n^6[\frac{12}{n^6}+2]} \\\\=\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{n^4[\frac{12}{n^6}+2]}

\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n=\sum_{n=1}^{inf} \frac{1}{n^4}

Now:

\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\ \\\lim_{n \to \infty} a_n = \lim_{n \to \infty}  \frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\=\frac{7-\frac{4}{inf}+\frac{3}{inf}}{\frac{12}{inf}+2}\\\\=\frac{7}{2}

So a_n is finite, so it converges.

Similarly b_n converges according to p-test.

P-test:

General form:

\sum_{n=1}^{inf}\frac{1}{n^p}

if p>1 then series converges. In oue case we have:

\sum_{n=1}^{inf}b_n=\frac{1}{n^4}

p=4 >1, so b_n also converges.

According to comparison test if both series converges, the final series also converges.

It means \sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6} also converges.

5 0
3 years ago
What is the length of arc QR? <br> A. 1/3 π<br> B. 10/3 π<br> C. 5/3 π<br> D. 20/3 π
podryga [215]
D. 20/3 I think it’s the answe
3 0
3 years ago
The tail of a Boeing 747 is 63 2/3 feet.<br> How many inches tall is the tail?
mixas84 [53]

Answer:

1 foot is 12 inch so the tail of boeing will be 63 2/3 x 12

Step-by-step explanation:

brainly.com/question/3663351

Hoped this helped and have a nice day

3 0
2 years ago
Read 2 more answers
A candy store sells chocolate for ​$5.94 per pound. The piece you want to buy weighs 0.23 pound. How much will it​ cost, to the
Charra [1.4K]
5.94 is for one pound. 0.23 is the same as 23%
To find 23% of 5.94, take 0.23 time the price.
0.23 x 5.94 = 1.3662. The nearest cent is 1.37.
$1.37
8 0
3 years ago
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