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2 years ago

11 A right triangle is shown.

Mathematics

1 answer:

Gre4nikov [31]2 years ago

3 0

Answer:

8 in.

Step-by-step explanation:

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I need help. i don't understand this at all.

Sauron [17]

Answer:

Step-by-step explanation:

If this is in terms of angles, 4x+6 must be equal to 90 since it is half of the angle produced by a line (180°) So solving for 4x+6=90, x=21

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2 years ago

Read 2 more answers

The area of a right triangle with one leg measuring 5 ft. and hypotenuse measuring 13 ft. is_______ a0. Type a numerical answer

Snowcat [4.5K]

Area of the triangle = (1/2)*base*height

For right triangle base and height can be legs.

We have one leg = 5 ft. (Lets think it is a base.)

We need to find the other leg.

We are going to use Pythagorean theorem.

5² + b²=13²

b²=144

b=12 (It is going to be our height.)

Area of the triangle = (1/2)*5*12= 30 ft²

Area of the triangle = 30 ft²

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3 years ago

Linear System Word Problem - Animals

Margaret [11]

Answer:

There were 15 birds at the shelter on Monday

Step-by-step explanation: 15 birds x 5$ =75$ and 8 cats x 6$=48$ 75$ + 48$=123$

4 0

2 years ago

What is the largest possible integral value in the domain of the real-valued function

kotegsom [21]

Answer:

Max Value: x = 400

General Formulas and Concepts:

Algebra I

Domain is the set of x-values that can be inputted into function f(x)

Calculus

Antiderivatives
Integral Property: $\int {cf(x)} \, dx = c\int {f(x)} \, dx$
Integration Method: U-Substitution
[Integration] Reverse Power Rule: $\int {x^n} \, dx = \frac{x^{n+1}}{n+1} + C$

Step-by-step explanation:

Step 1: Define

$f(x) = \frac{1}{\sqrt{800-2x} }$

Step 2: Identify Variables

Using U-Substitution, we set variables in order to integrate.

$u = 800-2x\\du = -2dx$

Step 3: Integrate

Define: $\int {f(x)} \, dx$
Substitute: $\int {\frac{1}{\sqrt{800-2x} } } \, dx$
[Integral] Int Property: $-\frac{1}{2} \int {\frac{-2}{\sqrt{800-2x} } } \, dx$
[Integral] U-Sub: $-\frac{1}{2} \int {\frac{1}{\sqrt{u} } } \, du$
[Integral] Rewrite: $-\frac{1}{2} \int {u^{-\frac{1}{2} }} \, du$
[Integral - Evaluate] Reverse Power Rule: $-\frac{1}{2}(2\sqrt{u}) + C$
Simplify: $-\sqrt{u} + C$
Back-Substitute: $-\sqrt{800-2x} + C$
Factor: $-\sqrt{-2(x - 400)} + C$

Step 4: Identify Domain

We know from a real number line that we cannot have imaginary numbers. Therefore, we cannot have any negatives under the square root.

Our domain for our integrated function would then have to be (-∞, 400]. Anything past 400 would give us an imaginary number.

7 0

2 years ago

NEED HELP ON THIS QUESTION

Tom [10]

Answer: 288

Workings : 16 x 12 =192 (for bottom rectangle bit) 12x 16 =192 then divide 192 by 2 =96 add them together and its 288

3 0

2 years ago