Answer:
L=6x^2-4x+5
P=12x^2-4x-2
Step-by-step explanation:
A=WL
So, we know the area is 6x^2-8x-30 and the width is 2x-6
Substitute
(6x^2-8x-30)=(2x-6)(L)
L=(6x^2-8x-30)/(2x-6
Divide
L=6x^2-4x+5
P=2L+2W
Substitute
P=2(6x^2-4x+5)+2(2x-6)
P=12×^2-8x+10+4x-12
Simplify
P=12x^2-4x-2
Answer:
Step-by-step explanation:
The null and alternative hypothesis are usually used in hypothesis testing to present the claim being tested as give in terms of the mean or proportion :
Given that the mean score of high school students is 10 ; using a sample of 50 students, a mean of 8 was obtained ; we could want to test the claim that the mean score is less than 10.
Here; population mean, μ = 10 ; the claim is now that, μ < 10 based on what was observed about the sample.
H0 : μ = 10
H0 : μ < 10
If we wanted to test If the mean was greater than 10 ; then the sign is reversed
H0 : μ = 10
H0 : μ > 10
If we wanted to test If the score is just different from the mean score stated ; (it may be less than or greater than)
H0 : μ = 10
H0 : μ ≠ 10
The child's starting and finishing location is the same, therefore the displacementnis zero.
Hey there!
To figure out what "x" means, you can divide the numbers 126 and 14 . . .
126 divided by 14 = 9
9 x 14 = 126
9 = x
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x = 9
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Hope this helps you.
Have a great day!
Answer:
6
Step-by-step explanation:
