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Mama L [17]
2 years ago
6

Which expression is equivalent to 0.7×0.23

Mathematics
2 answers:
Len [333]2 years ago
8 0

Answer:

o D (7x\frac{1}{10} )x(23x\frac{1}{100})

Step-by-step explanation:

0.7×0.23

is equivqlent to:

(7 x 1/10) x (23 x 1/100)

Marina CMI [18]2 years ago
3 0
The answer is D because when multiplied by 1/10 you move the decimal place of 7 one space to the left so 7 now equals .7 and when multiplied by 1/100 23 is moved two spaces to the left to make .23
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The body weight of a healthy 3 month-old colt should be about μ = 60 kg. (Source: The Merck Veterinary Manual, a standard refere
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Answer:

a

  The null hypothesis will be  H_o : \mu = 60 \ kg

b

  The alternative hypothesis will be  H_a : \mu <  60

c

  The alternative hypothesis will be  H_a : \mu >  60

d

  The alternative hypothesis will be  H_a : \mu \ne   60

e

  left; right; both

Step-by-step explanation:

Considering question a

    The body weight of the colt is  \mu = 60 \ kg

    The null hypothesis will be  H_o : \mu = 60 \ kg

Considering question b

    Given that we want to test the claim that the average weight of a wild Nevada colt is less than 60 kg , then

The alternative hypothesis will be  H_a : \mu <  60

Considering question c

       Given that we want to test the claim that the average weight of such a wild colt is greater than 60 kg , then

The alternative hypothesis will be  H_a : \mu >  60

Considering question d

   Given that we want to test the claim that the average weight of such a wild colt is different from 60 kg , then

The alternative hypothesis will be  H_a : \mu \ne   60

Considering question e

   For question b  , the corresponding p-value will be on the left because the average weight is less than 60 kg

   For question c  , the corresponding p-value will be on the right  because the average weight is more than 60 kg

   For question d  , the corresponding p-value will be on both  because the average weight is different from  60 kg

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Step-by-step explanation:

Hope this helped lol

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